Suppose you know the base of a rectangle has a length of 4 inches and a diagonal has a length of 5 inches. Find the area of the rectangle.

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Answer 1
Answer:

The area of the rectangle is A = 12 inches²

What is the Area of a Rectangle?

The area of the rectangle is given by the product of the length of the rectangle and the width of the rectangle

Area of Rectangle = Length x Width

Given data ,

Let the area of the rectangle be A

Let's use the Pythagorean theorem to find the length of the other side of the rectangle.

Let's call the length of the other side "x".

Using the Pythagorean theorem, we have:

x^2 + 4^2 = 5^2

Simplifying and solving for x, we get:

x^2 + 16 = 25

x^2 = 9

x = 3

So the length of the other side of the rectangle is 3 inches.

To find the area of the rectangle, we multiply the length by the width:

Area of rectangle A = length x width = 4 x 3 = 12 inches²

Hence , the area of the rectangle is 12 square inches

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Answer 2
Answer: That diagonal will split the rectangle into two triangles, with 5 inches being the hypotenuse of each. If we know that one base is 4 inches, then we can use the Pythagorean theorem to find the length of the other side of the rectangle. Let's call that other side x for now. x^2+4^2=5^2, because of the pythagorean theorum. 
x^(2) +4^(2) = 5^(2)
x^(2) +16=25
x^(2) =9
x=3
So 3 is the other side of the rectangle, take that times 4 and you'll get 12 in^2.


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