Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the progeny will be expected to phenotypically resemble the first parent? A) 1/4
B) 1/8
C) 3/4
D) 3/8
E) 1

Answers

Answer 1
Answer: The answer is C) 3/4

Let's analyze separately each of the traits:

Parental generation: AA x Aa
F1 generation:       AA AA Aa Aa
So, all progeny will phenotypically resemble the first parent.

Parental generation: BB x bb
F1 generation:       Bb Bb Bb Bb
So, all progeny will phenotypically resemble the first parent.

Parental generation: Cc x Cc
F1 generation:       CC Cc Cc cc
Only 3 (CC, Cc, Cc) out of 4 progeny will phenotypically resemble the first parent.

The genotypes for first two traits will not affect 
phenotypical resemblance to the first parent. So, it only counts the third trait, for which the chance to have progeny that phenotypically resemble the first parent is 3/4.
Answer 2
Answer:

To determine the proportion of progeny that will phenotypically resemble the first parent, we need to consider the inheritance of each trait independently. From this, the correct answer is option C) 3/4

Parent AABBCc can produce gametes with the following allele combinations:

ABc, ABc

Parent AabbCc can produce gametes with the following allele combinations:

aBC, aBC

When these gametes combine, the possible genotypes of the progeny are:

ABCaBC, ABCaBC, ABcaBC, ABcaBC

Among these genotypes, three out of the four have the same phenotype as the first parent (AABBCc). Therefore, the proportion of progeny expected to phenotypically resemble the first parent is 3/4.

Hence, the correct answer is C) 3/4.

Learn more about inheritance here:

brainly.com/question/31824780

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