Vickie made a recipe for 144 fluid onces of scented wax How many 1 cup candle molds can she fill with the recipe

Answers

Answer 1

Answer: One cup is approximately 8 ounces, so if Vickie has 144 ounces of scented wax you'd divide it by 8. So the answer is 18.

Related Questions

Solve this equation -8-x=x-4x
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Spencer took $21 with him to the mall. At the music store he spent 2/3 of his money on a DVD. Then spent 1/4 on a drink. How much money does spencer have left?

Answers

After the music store he had $14 left, because 21:3=7 and 7x2 equals 14.

After the drink, he has $3.5 left, because 14:4=3.5 and 3.5x1=3.5.

Conclusion: that is one expensive drink. (Answer is 3 dollars and 50 cents. Hope this helped:)

Ok to solve this problem we need to first find how much he spend in the mall. We put the 2 fractions into like denominators which is 12. If we convert it we get a total of 11/12. So he spent 11/12 of his money. One way you can solve is by figuring out how much 11/12 is and subtract that by 21. Then you will get 19.25
21 minus 19.25 is 1.75 dollars. Another way is to just find out how much is 1/12 of 21. Then you will get $1.75. So Spencer has 1.75 dollars left. I hope this helps!

Your new cell phone plan costs $45 per month. You pay an extra $0.05 for every text message sent. If you send 60 texts this month, how much will your bill be?

Answers

it would be $48 for that month because if you multiply 0.05 and 60 its 3.00 and then you add 45+3 and get 48

$48 is the cost this month. You multiplied 60 and $0.05, and then added $45.

It takes Sarah 50 minutes to walk to her friend's house 1 3/4 miles away. What is her walking pace in miles per hour?

Answers

Divide 50 by 1 3/4 to get your answer for miles per minute then multiply that by sixty to get hours. then write it as _mph

Solve: 3x - 2x + 4 = 5x - 4x - 8

Answers

Answer:

No solution for the given algebraic expression.

Step-by-step explanation:

To solve the algebraic equation we must isolating the variable or rewriting the equation so that the one expression is only the variable with the coefficient 1.

Solve: $3x-2x+4=5x-4x-8$

Now put every terms that contains variables on one side of the equation and those terms on the other side which does not contains the variable.

$3x-2x-5x+4x=-4-8$

Combine like terms:

$x-x=-12$

$0=-12$ which is not true.

therefore, the given expression have NO SOLUTION.

The equation $3x-2x+4=5x-4x-8$ has $\boxed{\text{\bf no solution}}$ .

Further explanation:

Given:

The equation is $3x-2x+4=5x-4x-8$ .

Calculation:

The above equation involves only one variable.

To solve a one variable linear equation, arrange all the terms that contain variable on one side and the terms that are free from variable on the other side.

Write the given equation by taking terms that contains variable on left side and the terms which are free from variables on right side.

Subtract $(5x-4x)$ from both the sides of the given equation.

$\begin{aligned}3x-2x+4&=5x-4x-8\n3x-2x-5x+4x+4&=5x-4x-8-5x+4x\n7x-7x+4&=-8\end{aligned}$

Subtract $4$ from both the sides of the above equation,

$\begin{aligned}7x-7x+4-4&=-8-4\n0&=-12\end{aligned}$

The above equation shows that the value of $0$ is equal to $-12$ .

The statement “0 is equal to -12” is a false statement.

Therefore, the equation $3x-2x+4=5x-4x-8$ has no solution.

No solution means there exists no value of $x$ that satisfies the given equation.

Learn more:

1. Solution of linear equation ://brainly.com/question/1682776

2. Equation of line brainly.com/question/1473992

3. A problem on intercept brainly.com/question/1473992

4. A problem on composite function brainly.com/question/2723982

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Linear equation

Keywords: Equation, variable, 3x - 2x + 4 = 5x - 4x – 8, constant, linear equation, no solution, solve, addition, subtraction, isolate, plug, substitute.

Classify the system and identify the number of solutions.2x + y + 5z = 4
3x − 2y + 2z = 2
5x − 8y − 4z = 1

Answers

Answer:

No solutions

Step-by-step explanation:

We need to eliminate one of the variables to solve the system. To do so, let's multiply the first equation by 8, the second equation by 4

2x + y + 5z = 4 (1) x 8
3x − 2y + 2z = 2 (2) x 4
5x − 8y − 4z = 1 (3)

The system becomes:

16x + 8y + 40z = 32 (1)
12x - 8y + 8z = 8 (2)
5x - 8y - 4z = 1 (3)

Add (1) and (2), subtract (3) from (2) to eliminate y

28x + 48z = 40 (4)
7x + 12z = 7 (5)

Then multiply the equation (5) by 4 to compare with(4)

28x + 48z = 28

Comparing the equations (4) and (5) we see it has no solutions as both variables have same coefficient but with different sum, 28≠40

Answer:

inconsistent; none

What is the solution to the equation 1/3(9x-6)=2x+3

Answers

remember, you can do anything to an equaiton as long as you do it to both sides

try to get the unknown by itself

distributive property
a(b-c)=ab+ac

distribute first
1/3(9x-6)=9/3x-6/3=3x-2

now we have

3x-2=2x+3
minus 2x boh sies
3x-2x-2=2x-2x+3
1x-2=0+3
add 2 both sides
x+2-2=3+3
x+0=5
x=5

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