Jesse is putting a ribbon around a square frame he uses 24 inches of ribbon how long is each side of the frame

Answers

Answer 1

Answer: Each side of the frame is 6 inches long

Answer 2

Answer: Each is 6 inches long✌️

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What is 11*1/4 for math

Answers

2.75 is the answer the your question

first, make 11 a fraction like 1/4
11 becomes 11/1
then multiply the numerators 11*1 = 11
then multiply the denominators 1*4
So, your answer would be

11/4 which simplifies to 2 3/4

60 paintings. T= Painting from 20th century. B= British painting. A painting is chosen random.it is from the 20 century. Work out the probability it is British

Answers

The probability will be "0.20".

According to the question,

The sum of all the areas = 60

then,

$x(x-2)+x+(2x+8)+10=60$
$x=6$

Therefore,

→ $P (British | It's \ from \ the \ 20^(th) \ century) = (n(B \ and \ T))/(n(T))$

$= (x)/(x+x(x-2))$

$= (6)/(6+6(6-2))$

$= (1)/(5)$

$= 0.20$

Thus the answer above is right.

Learn more:

brainly.com/question/6133405

Final answer:

This question is about computing the conditional probability that a painting selected at random is British, given it's from the 20th century. Without specific numbers, the tentative solution is the ratio of the number of British 20th-century paintings to the total number of 20th-century paintings.

Explanation:

The subject here is Probability, a topic within Mathematics. Let us assume without losses in generality that 'T' represents a painting from the 20th century and 'B' represents a British painting. Given 60 paintings, we're selecting one at random. The condition is it's a 20th-century painting ('T') and we need to find the probability that it's also a British painting ('B'). The data given in the question isn't clear enough to give a numerical answer. However, we can give a general solution.

Firstly, we find the number of paintings which are both from 20th century and British. Let's say this number is n. The number of 20th-century paintings would be more than or equal to n. Let's call this N. Therefore, the required probability would be n/N.