Answer:
Explanation:
Kinetic energy is the energy in motion. Cooling if liquid would cause decreased temperature and hence slow down the oscillation of the particles.
Likewise, increased heat reduces the force of attraction between said particles, which allowed for their free movement. So the cooling would have opposite effect.
Finally, the space between the particles would remain the same as it was originally, as their force of attraction is increased in the cooling process, they would take the form they are held in.
I hope this was helpful and concise?
Answer:
Explanation:
okay so first add two to four and the ten
Explanation:
Below is an attachment containing the solution
Answer:
pH= 0.369
Explanation:
The formic acid reacts with NaOH as
HCOOH + NaOH= HCOONa + H2O
Apply CaVa/ CbVb = Na/Nb
Ca×25/(29.8×0.3587) = 1/1
Ca= (29.8×0.3587)/25= 0.428M
pH = - log(H+)
Since only 0ne H+ is in the stoichiometric equation, it means H+ = 0.428M
pH = -log(0.428) =0.369
Answer:2.50 moles of magnesium will consume approximately 182.30 grams of hydrochloric acid in the given reaction.
Explanation:To find out how many grams of hydrochloric acid (HCl) are consumed when 2.50 moles of magnesium (Mg) react with it, you can use stoichiometry and the balanced chemical equation:
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
From the balanced equation, you can see that 1 mole of magnesium (Mg) reacts with 2 moles of hydrochloric acid (HCl).
Now, let's use this information to calculate the moles of HCl required to react with 2.50 moles of Mg:
Moles of HCl = (2.50 moles Mg) * (2 moles HCl / 1 mole Mg)
Moles of HCl = 2.50 moles * 2
Moles of HCl = 5.00 moles
Now that we know we need 5.00 moles of HCl, we can calculate the grams of HCl needed using the molar mass of HCl:
The molar mass of HCl is the sum of the atomic masses of hydrogen (H) and chlorine (Cl):
Molar mass of HCl = 1.01 g/mol (for hydrogen) + 35.45 g/mol (for chlorine)
Molar mass of HCl = 36.46 g/mol
Now, calculate the grams of HCl:
Grams of HCl = (5.00 moles) * (36.46 g/mol)
Grams of HCl = 182.30 grams
So, 2.50 moles of magnesium will consume approximately 182.30 grams of hydrochloric acid in the given reaction.