Answer:
Step-by-step explanation:
In order to solve the question, we have to derivate each function.
1) f(x) = x2 +4x -11
Then,
f'(x)= 2x +4
Now, if f'(4)=0 we would have a critical point, which could be a minimum. Let's find out:
f'(4)= 2*4 +4 = 12 ≠ 0 then this function doesn't not have a minimum at (4, -3)
2) f(x) = –2x2 + 16x – 35
Then,
f'(x)= -4x +16
Now, if f'(4)=0 we would have a critical point, which could be a minimum. Let's find out:
f'(4)= -4*4 16 = 4 ≠ 0 then this function have a critical point at (4, -3)
then,
f''(4) =-4 <0 then we have a minimum at (4, -3)
3) f(x) = x2 – 4x + 5
Then,
f'(x)= 2x -4
Now, if f'(4)=0 we would have a critical point, which could be a minimum. Let's find out:
f'(4)= 2*4 -4 = 4 ≠ 0 then this function doesn't not have a minimum at (4, -3)
4) f(x) = 2x2 – 16x + 35
Then,
f'(x)= 4x -16
Now, if f'(4)=0 we would have a critical point, which could be a minimum. Let's find out:
f'(4)= 4*4 -16 = 4 ≠ 0 then this function doesn't not have a minimum at (4, -3)
Marisol is painting on a piece of canvas that has an area of 180 square inches. The length of the Painting is 1 1/4 times the width. What are the dimensions of the painting
II
III
IV
The number 6 - 8i is located in the thirdquadrant of the complex plane.
Option C is the correct answer.
The term "quadrants" usually refers to the four regions of the Cartesian plane, which is a two-dimensional coordinate system.
The plane is divided into four regions called quadrants, labeled I, II, III, and IV, which are numbered counterclockwise starting from the upper right quadrant (I).
Quadrant I: The point has positive x and positive y coordinates.
Quadrant II: The point has negative x and positive y coordinates.
Quadrant III: The point has negative x and negative y coordinates.
Quadrant IV: The point has positive x and negative y coordinates.
We have,
To determine the quadrant where the complexnumber 6 - 8i is located, we need to consider the signs of the real and imaginary parts of the number.
The realpart of the number is 6, which is positive, indicating that the number lies to the right of the origin.
The imaginarypart of the number is -8i, which is negative, indicating that the number lies below the origin.
Therefore,
The number 6 - 8i is located in the thirdquadrant of the complex plane.
Learn more about quadrants here:
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Answer:
IV
Step-by-step explanation:
The 6 is to the right of the x axis ( positive x) and the -8i is below the x axis to the right.
Answer:
see below
Step-by-step explanation:
y = x+.6
Solve for x
Subtract .6 from each side
y-.6 = x+.6 -.6
y-.6 =x
Let y = 3 y-.6 = 3-.6 = 2.4 =x x=2.4
Let y=4.2 y-.6 = 4.2 - .6 = 3.6 =x x=3.6
Let y =2 y-.6 = 2-.6 =1.4 =x x=1.4