Let x be the rate of speed of slower cyclist
and x+10 = rate of speed of faster cyclist
Distance = Speed * Time
5x + 5(x+10) = 200
5x + 5x + 50 = 200
10x = 200-50
10x = 150
x = 15
Rate of speed of slower cyclist: 15 mph
Rate of speed of faster cyclist = 15+10 => 25 mph
In this problem, the speed of the faster cyclist is 25 mi/h and the speed of the slower cyclist is 15 mi/h. We determine this by setting up and solving an algebraic equation considering the total distance and time they traveled.
This problem is a typical example of relativerate and distance problems in algebra. First, define the speed of the faster cyclist as x m/h. Then, the speed of the slower cyclist is x-10 m/h. They travel towards each other, so their rates add up. That's why the equation becomes x+(x-10) = 200/5. We get this equation because the total distance they traveled is 200 miles (meeting in the middle), and they traveled for 5 hours.
Solving the equation x+(x-10) = 40 gives 2x-10 = 40, then 2x = 50, and finally x = 25. So, the faster cyclist is moving at 25 mi/h, and the slower cyclist is moving at 15 mi/h (25-10).
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I'd say an outlier. P is separated noticably from the other points and would not considerably affect the slope of the line
Answer:
An outlier
Step-by-step explanation:
The point P is quite separate from the rest of the data.