0.8 divided by 0.64.

Answers

Answer 1

Answer: IT's just a simple conversion.
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Ok. So, when you divide with decimal places, you have two options -
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Suck it up and divide, or move the decimal places to the right as many times as needed, until the number is a whole number.
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Choosing to move the decimal places to the right is the easy way out...
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So?
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Move decimal point to the right two places in both numbers!!
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80 and 64.
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So what is 80/64?
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You got it!!
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1.25.
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Hope I helped!!

Answer 2

Answer: .8 divided by .64 is 1.25

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What is the average of the scores 90 and 40??

Answers

the first thing you do is add 90 and 40, which gives you 130... after that you just divide that sum by 2 giving you an average of 65

A plastic box is 15.3 centimeters long 9.0 centimeters wide and 4.5 centimeters high what is its volume. includes units and your answer

Answers

15.3*9*4.5=619.65 cubic cm or $cm^3$

Answer:

619.65 cm³

Step-by-step explanation:

V= L x w x h = 15,3 x 9.0 x 4.5 = 619.65 cm³

The image shows a right triangle in the coordinate plane. What is the measure of segment DF?

Answers

Answer:

10.8 units

Step-by-step explanation:

Answer:

10.8

Step-by-step explanation:

Its True

A student walks 8 meters down the hall, realizes they forgot something from their locker andturns around and walks back 2 meters. Calculate their net displacement.

Answers

Answer:

6 meters

Step-by-step explanation:

8 - 2 = 6

Rajan bought a suit for rs 2995. he paid 7% sales tax on it. what did he pay in total

Answers

the text price gonna be : 7/100% = ?/2995 ⇒ 2995 * 7 / 100 = 209 .65 so the total price is : 2995 + 209.65 = 3204.65 :)))
i hope this be helpful
have a nice day

How to work math problem -7/9(x=3)=14

Answers

$-(7)/(9)(x+3)=14\ \ \ \ \ |multiply\ both\ sides\ by\ (-(9)/(7))\n\n(-(\not9^1)/(\not7_1))*(-(\not7^1)/(\not9_1))(x+3)=-(9)/(7)*14\n\nx+3=-9*2\n\nx+3=-18\ \ \ \ \ |subtract\ 3\ from\ both\ sides\n\n\boxed{x=-21}$

-7/9(x=3)=14

-7/9x-7/3=14 (distribute)
-7/9x=49/3 (add 7/3 to both sides)

x=-21 (divide 49/3 by -7/9)

you can check if its correct by substituting back into the original equation

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