MATHEMATICS HIGH SCHOOL

The numbers 4, 5, 6, and 7 are on a spinner. You spin the spinner twice. Which calculation proves that landing on an even number for the first spin and the second spin are independent events?

Answers

Answer 1

Answer:

Not sure what that dude is even saying. The answer is C- P(A and B)=2/4*2/4

Hope this helped.

Answer 2

Answer:

Answer:

As long as the numbers are in equal proportion on the spinner, the probabilty of landing on an even number for the first and second spin is 1/4, or 25%.

Step-by-step explanation:

If there are four numbers on a spinner, all in equal proportion, than the probability of getting an even number (either 4 or 6) on any spin is 2/4, or 1/2, which is also 50%. Since the results of the first spin do not influence the results of the second spin, then they are independent events. So, if the likelihood of landing on even each time is 1/2, then we would mutliply 1/2 by 1/2 in order to find the probability that landing on an even number would happen in both spins. Our result would be 1/4, or 25%.

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A table is rectangular and its length is twice its width. Find the dimensions of the table if it occupies 18 ft2 of floor space.

Answers

the dimensions of the table width would be 2 feet and the length would be 4 feet.

The answer would be length is 6, and width would be 3.
How to find the answer:
First you make combinations that multiply to 18 (because area is length times width)
2 x 9
3 x 6
6 x 3
9 x 2
since the last two are basically the same as the first two, you can get rid of those.
2 x 9
3 x 6
since 3 is half of 6 (and 2 isn't half of 9),
3 x 6 is the answer.
Hope this helps.

There are 3 red gumdrops and 2 green gumdrops in a small jar.Also, 4 pieces of butterscotch candy and 1 piece of cinnamon candy are in another jar. If craig draws one piece of candy from from each jar without looking? what is the probability that he will get a red gumdrop and a piece of cinammon candy?

Answers

I don't really understand your question. You claim he draws one piece of candy, then ask for the probability of a red gumdrop followed by a cinnamon candy. Regardless, I'll just answer the latter question (Assuming they're not replaced):

3+2+4+1 = 10

3/10 x 1/9 = 0.033333 or 1/30

The answer fir the red gumdrops is 60%. The answer for the cinnamon candy is 20%.

What angle do the minute and hour hands of a clock make at 10:00

Answers

The hour hand is at 10 and the minute at the 12. If a clock is seen divided into 12 parts and there's 360° in a circle so 360/12=30° between two numbers.
Between 10 and 11 is 30°, between 11 and 12 is 30° so between 10 and 12 is 60°

Find the slope of the line through each pair Of points.1. (1,5) and (2,8)
2. (3,1) and (3,-1)

Answers

In order to find the slope between a set of points you must plug the points into the point slope formula ; ( y2-y1 / x2-x1 )

Once you plug that in you should get the final answers of

1. slope = 3

2. slope = -2/0 which is undefined which means this slope would be part of a vertical line

Twiddle_de_dumIf ΔAED is dilated to points A, C, and B, which statement is true?
A) ΔAED ~ ΔACB
B) ΔAED ≅ ΔACB
C) The area of ΔAED is half the area of ΔACB
D) The perimeter of ΔAED is one-fourth the area of ΔACB

Answers

I saw the image of the triangle. It is a right triangle.

AD is the long leg ; AE is the short leg ; DE is the hypotenuse

AD = 3 ; AE = 2 ; DE = 3.61 (use Pythagorean theorem)
Perimeter = 3 + 2 + 3.61 = 8.61

Area of a right triange = (3*2)/2 = 6/2 = 3 square unit

Dilated to ACB
AB is the long leg ; AC is the short leg ; BC is the hypotenuse
AB = 6 ; AC = 4 ; BC = 7.21
Perimeter = 6 + 4 + 7.21 = 17.21

Area of a right triangle = (6*4)/2 = 24/2 = 12 square unit

its a bc i hade this on a test and its a and i got it right so a.

Here are the possible outcomes when a pair of fair dice is rolled.1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12

In a roll of a pair of fair dice, what is the probability of the outcome being either a multiple of 3 or an even number? Are these events mutually exclusive?
, mutually exclusive
, not mutually exclusive
, mutually exclusive
, not mutually exclusive

Answers

I don't understand the big table of numbers at the top at all,
and don't see how it relates to the question.

There are 36 possible outcomes for the roll of a pair of dice.
According to your specifications, the successes are:

-- Multiples of 3:
   1 ... 2 (3)
   2 ... 1
   3 ... 3 (6)
   1 ... 5
   5 ... 1
   2 ... 4
   4 ... 2
   3 ... 6 (9)
   6 ... 3
   4 ... 5
   5 ... 4
   6 ... 6 (12)
(12 different outcomes)

-- Even numbers:
   1 ... 1 (2)
   1 ... 3 (4)
   3 ... 1
   2 ... 2
   3 ... 3 (6)
   1 ... 5
   5 ... 1
   2 ... 4
   4 ... 2
   2 ... 6 (8)
   6 ... 2
   3 ... 5
   5 ... 3
   4 ... 4
   4 ... 6 (10)
   6 ... 4
   5 ... 5
   6 ... 6    (12)
(18 different outcomes)

The events are NOT mutually exclusive.
A roll of 6 (5 ways) or 12 (1 way) meets both requirements.

Successful outcomes:
Multiples of 3 . . . . 12
Even numbers . . . 18
       Duplicates . . . . 6

So there are 24 different successful outcomes.

Probability = (24) / (36) = 2/3 = (66 and 2/3) %

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