The displacement vector, d, can be recomposed as follows: d = (Dx, Dy) and the magnitude of the displacement vector is approximately 11.24 meters.
To recompose the displacement vector, d, using the given X and Y components, you can use vector addition. The X and Y components represent the horizontal and vertical displacements, respectively.
Given:
Dx = 6.68 m (left)
Dy = 9.04 m (down)
The displacement vector, d, can be recomposed as follows:
d = (Dx, Dy)
So, the displacement vector is (6.68 m left, 9.04 m down). This means that the object moved 6.68 meters to the left (in the negative X direction) and 9.04 meters downward (in the negative Y direction) from its starting point.
The magnitude of the displacement can be found using the Pythagorean theorem:
|d| = √((Dx)^2 + (Dy)^2)
|d| = √((6.68 m)^2 + (9.04 m)^2)
|d| ≈ √(44.49 m^2 + 81.72 m^2)
|d| ≈ √(126.21 m^2)
|d| ≈ 11.24 meters
So, the magnitude of the displacement vector is approximately 11.24 meters.
Learn more about displacement vector here:
#SPJ1
Answer: Workdone293.02KJ
Explanation: The equation to use to calculate Workdone = Change in KE + Change in PE
Assuming velocity is constant,KE becomes 0
Workdone= Change in PE=mg
W=92×9.8×325=293.02KJ
tsunami waves
breakers on an ocean beach
waves created by a passing motor boat
Answer: Option (b) is the correct answer.
Explanation:
Tsunami is formed due to the underwater disturbances or underwater earthquake.
Tsunami has long wavelengths due to which it behaves as a shallow water wave and these waves propagate at very high speed with high energy and limited energy loss.
As a result, tsunami is able to cause huge and massive destruction to areas it is surrounding.
Thus, we can conclude that tsunami waves are the water waves which has more energy.
Tsunami Waves or option B would be your answer.