x = 3
"Standard form" is the form ...
... ax + by = c
where a, b, c are mutually prime integers. The coefficients a and b cannot both be zero. The leading coefficient must be positive. If "a" is zero, then the leading coefficient is "b".
So ...
... x = 3
is in standard form already. (a=1, b=0, c=3)
_____
Further comments on Standard Form
Of course, if the line has irrational slope or intercept, the coefficients cannot all be integers.
The order of the variables may be swapped, in which case the coefficient of y is the leading coefficient and must be positive.
This is the only way a vertical line can be written, as slope-intercept form is undefined for a vertical line.
Show the work please
Answer:
x=-3
Step-by-step explanation:
12-3x=-6x
12=-3x-6x
12= -9x
----------
-9. -9
12/9= -3
B. The graph would shift down 5 units.
C. The graph would shift up 5 units.
D. The graph would shift 5 units to the left.
Consider the function y=x^2+5x-2 . What would happen to the graph if (x + 5) was substituted in place of the x?
A. The graph would shift 5 units to the right.
B. The graph would shift down 5 units.
C. The graph would shift up 5 units.
D. The graph would shift 5 units to the left.
Option: D is the correct answer.
D. The graph would shift 5 units to the left.
We know that the transformation of a function f(x) to f(x+a) is a shift of the function either to the left or to the right by a units depending on the sign of a i.e. if a>0 then the shift is a units to the left
and if a<0 then the shift is a units to the right.
Here we have:
is converted to:
Here we have a=5>0
Hence, the shift is 5 units to the left.
Answer: -5
Step-by-step explanation:
7x4+6-12/4
Answer:
31
Step-by-step explanation:
7×4+6-12÷4
multiply 7 and 4
28+6-12÷4
12÷4=3
28+6-3
28+6=34
34-3=31
anwer=31