I have two-thirds of a square and I want to divide it by one-half. How many pieces would I have?
Answers
Answer:2 pieces or 1 1/3
Step-by-step explanation:
cause if 2/3 was 1 piece and you divide by 1/2 you have double what you had making you have 2 pieces
Final answer:
Dividing two-thirds by one-half results in one and one-third pieces.
Explanation:
To divide two-thirds of a square by one-half, you can multiply the fractions. This is a division of fractions problem. You have two-thirds (2/3) of a square and you want to divide it by one-half (1/2). In division of fractions, you multiply by the reciprocal of the divisor. So, you would change the division to a multiplication and flip the second fraction (1/2 becomes 2/1). Therefore, (2/3) divided by (1/2) becomes (2/3) * (2/1). When we multiply these fractions, we get (4/3) or one and one-third. So, you have one and one-third pieces.
Learn more about Division of Fractions here:
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Related Questions
A system in a noisy environment transmits 11111 or 00000 when 1 or 0 are transmitted to decrease the probability of error. Suppose the probability that one of the 5 transmitted bits is corrupted from 1 to 0 is 0.3 and the probability that a bit is corrupted from 0 to 1 is 0.1. Given that the probability that the system transmits a 0 or a 1 is equally likely, if 01101 was received what is the probability that a 1 was transmitted.
Find all the real square roots of 0.0064
Which is 23,578,000 written in scientificnotation?
± √2 write the quadratic eaquation with the given roots.
Answers
Answer:
Options (1), (3) and (7)
Step-by-step explanation:
Characteristics of the given graph are as followed.
1). For every input value (x-value) there is a different output values (y-values).
So the points on the graph represent a function.
2). Coordinates of all the points are distinct and separate (not in fractions or decimals).
Function given is a discrete function.
3). For every increase in the x-values of the points there is a decrease in y-values.
Therefore, given function is a decreasing function.
Therefore, Options (1), (3) and (7) are the correct options.
Driver B had a mean race time of 3.96 seconds and a standard deviation of 0.12 seconds.
Driver C had a mean race time of 3.99 seconds and a standard deviation of 0.19 seconds.
Answers
Answer: driver a
Step-by-step explanation: because the time was 4.01
Answers
Answer:
-22x-36
Step-by-step explanation:
-6 x 5x = -30x
-6 x 6 =-36
8x - 30x - 36
8x - 30x = - 22x
So, it's -22x - 36.
Answer:
-22 x- 36
Step-by-step explanation:
8x - 6(5x + 6)
-6× 5x= -30x
-6 × 6= -36
8x -30x - 36
-22x - 36
Answers
Answer:
The width of the deck is 2m .
Step-by-step explanation:
Let the width of the pool be represented by w. As stated in the problem a deck of uniform width is to be built so the total width of the pool and deck will be w+w = 2w.
Now the total dimensions can be taken as
10m+ 2w and 5m + 2w of both the pool and deck.
Area = length * breadth
126m ²= (10m+ 2w) ( 5m + 2w )
126= 50 + 30 w+ 4w²
0= 50 -126+ 30 w+ 4w²
0 = 30 w+ 4w²- 76
Taking 2 as common
0= 2( 15 w+ 2w² - 38)
2w²+ 15 w - 38= 0
The above equation is the quadratic equation and can be solved as follows.
a= 2 , b= 15 and c= -38
b= -b±√b²- 4ac/2a
Putting the values
b= - 15±√15²- 4( 2)(-38)/2(2)
b= - 15± 23/4
b= - 38/4 or 8/4
b= 2 m
The width cannot be negative so we ignore the negative value
The width of the deck is 2m .
The can be checked by putting the value in the original equation.
126m ²= (10m+ 2w) ( 5m + 2w )
126m ²= (10m+ 2(2)) ( 5m + 2(2) )
126m ²= (10m+ 4) ( 5m + 4 )
126m ²= 14*9
126m ²= 126m ²
Answers
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=
0=x^2+12x+16
a=1
b=12
c=16
x=
x=
x=
x=
x=
x=
aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721