The number of molecules of isopently acetate is 4.63 x 10¹⁵ molecules
calculation
Step 1: find the moles of isopently acetate( C₇H₁₄O₂)
moles = mass÷ molar mass
From periodic table the molar mass of C₇H₁₄O₂
= (12 x7 ) + (1 x14) +(16 x2) =130 g/mol
moles = 1 x10⁻⁶ g÷ 130 g/mol = 7 x 10⁻⁹ moles
step 2 ; use the Avogadro's law constant to calculate the number of molecules
That is according to Avogadro's law 1 mole = 6.02 x 10²³ molecules
7 x 10⁻⁹ moles = ? molecules
by cross multiplication
= { (7 x 10⁻⁹ moles x 6.02 x10²³ molecules) / 1 mole} = 4.63 x 10¹⁵ molecules
Answer:Answer:
5.8
×
N
A
, where
N
A
=
Avogadro's Number,
6.022
×
10
23
⋅
m
o
l
−
1
Explanation:
And
5.8
⋅
m
o
l
×
6.022
×
10
23
⋅
m
o
l
−
1
=
?
?
What is the mass of this quantity of lithium atoms? Hint, 1 mole has a mass of
6.94
⋅
g
.
Explanation:
i hope this helps
The net ionic equation for this reaction is . In ionic equations the soluble compounds are written in their dissociated ion forms. The ionic equation can be determined by knowing the general solubility rules. In this problem there are sulfate compounds involved. It is important to know that sulfates are generally soluble except for sulfates of Ba, Pb, Ag, and Sr. Therefore, the ones dealt with in this problem, CuSO4 and FeSO4, are both soluble in water.
Further Explanation:
The complete equation for this reaction is:
CuSO4 and FeSO4 are soluble in water which will lead to the ionic equation:
Since the sulfate ion appears on both sides, it is a spectator ion. Spectator ions are unchanged in the chemical reaction and are removed from the net ionic equation:
Based on the net ionic equation it can be seen that this is a reduction-oxidation reaction. Iron was oxidized and copper was reduced.
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Keywords: ionic equation, solubility
b. products, reactants
c. elements, atoms
d. reactants, products
The answer is letter D. Reactants, Products
One example would be the dissolving of molecules with water so that they can be transported.