Answer:
its B false
Explanation:
Production of sweat which functions in thermo-regulation (controlling the body temperature) is the function of the sweat glands.
Further Explanation:
Skin is the body's largest organ. The skin protects the inner body from the outer environment. The skin has different receptors for heat cold touch and pain. Tactile cells are found in the epidermis basal layer and are connected to the dermal nerve fiber that lies below. These are few in number and has contain the touch receptors. The skin has different types of cells which are specialized for specific functions. The dendritic cells present in the skin are responsible for the signals that alert the immune system to pathogens. The Langerhans cells protect the body by keeping away the antigens.
• Epidermis- Outermost layer which is responsible for the skin tone of a person. The most abundant protein in this layer is the keratin.
• Dermis- the layer beneath the epidermis which contains sweat glands, hair follicles and tough connective tissues. The highest found protein in this layer is collagen.
The dermal coat of the skin contains the glands like scent glands, sebaceous glands, eccrine glands etc. The secretions of these glands differ in functions as well as composition. The glands present in the dermal layer of the skin is responsible for the odour, protection, moisturization, and cleaning of the skin and body. The sebaceous glands produce sebum which is an oily substance usually beneficial for the lubrication of the skin.
Learn more:
1. Learn more about importance of sweat glands brainly.com/question/2904505
2. Learn more about location of sweat glands brainly.com/question/8373242
3. Learn more about reasons for sweating brainly.com/question/10790999
Answer Details:
Grade: High School
Subject: Health
Topic: Integumentary System
Keywords:
Skin, sweating, sweat glands, lubrication of the skin, cleaning of the skin, odour, protection, moisturization, Dermis, collagen, Epidermis, keratin, antigens.
Answer:
The body's mechanism to help you cool down. When your body temperature increases your body sweats (through your sweat glands) to help you cool down.
Explanation:
hope i helped
B. Polycythemia
C. Thalassemia
D. Thrombocytopenia
nformation for how many patients took each drug or combination of drugs is summarized below in the two tables. Use these to answer questions a) -d)
Table 1. Summary of performance of drug A: UTI rates among those taking and not taking drug ADid not take Drug ADid take Drug A
total UTI
759
887
164 No UTI
441 312 753Total 1200 1200
2400Table 2. Summary of performance of drug B and C: recovery status after 1 week of taking medications.
Did not take Drug A
Did take Drug A
Drug B
Drug C
Drug B
Drug C
Recovered
191
209
221
244
Not Recovered
189
170
223
199
Total
380
379
444
443
a. Use the above Table 1 to determine if Drug A was useful in preventing UTIs. In other words, is the proportion of those having taking Drug A but still getting a UTI equal to average rate of UTI for this population (living in an assisted living home) of 74%. Use hypothesis testing to test our hypothesis and use the confidence interval approach with a significance level of α=0.01.
b. Using Table 2, let’s examine the rate of UTI recovery among Drug C (conventional antibiotics). The manufacturer of Drug C claims it has a success rate (recovery within a week) of 55%. Use our data to see if this success rate is true: test if our recovery rate of those taking Drug C, regardless of whether the person took Drug A or not, is the same or different than 55%. Use hypothesis testing and the p-value approach with an α=0.05.
c. Similarly, let’s examine Drug B’s performance. Repeat our hypothesis among Drug B: test if our recovery rate of those taking drug B is different than 55% (regardless of whether the patient took Drug A or not). Use hypothesis testing and p-value approach with an α=0.1.
Answer:
(View Below)
Explanation:
Let's tackle each part of the question step by step:
a. **Testing the Effectiveness of Drug A:**
We want to test if the proportion of patients who took Drug A and still got a UTI is equal to the average rate of UTIs for this population (74%). We can use a hypothesis test for proportions. Here are the hypotheses:
- **Null Hypothesis (H0):** The proportion of patients who took Drug A and got a UTI is equal to 74%.
- **Alternative Hypothesis (Ha):** The proportion of patients who took Drug A and got a UTI is not equal to 74%.
We'll perform a two-tailed test at a significance level of α = 0.01.
Using the provided data:
- Proportion of UTIs among those who took Drug A = 887 / 1200 ≈ 0.7392
- Proportion of UTIs among those who did not take Drug A = 759 / 1200 ≈ 0.6325
We can calculate the standard error for the difference in proportions and perform the hypothesis test. I'll calculate the z-score and p-value for you:
Z = (0.7392 - 0.6325) / √[0.6325 * (1 - 0.6325) / 1200] ≈ 2.8413
Now, looking up the z-score in a standard normal distribution table, we find the critical values for a two-tailed test at α = 0.01 to be approximately ±2.576.
Since our calculated z-score (2.8413) is greater than the critical value (2.576), we can reject the null hypothesis.
Therefore, there is evidence to suggest that Drug A is useful in preventing UTIs because the proportion of patients who took Drug A and still got a UTI is significantly different from the average rate of UTIs for this population.
b. **Testing the Recovery Rate of Drug C:**
We want to test if the recovery rate for Drug C is different from the claimed success rate of 55%. We can use a hypothesis test for proportions. Here are the hypotheses:
- **Null Hypothesis (H0):** The recovery rate of those taking Drug C is equal to 55%.
- **Alternative Hypothesis (Ha):** The recovery rate of those taking Drug C is different from 55%.
We'll perform a two-tailed test at a significance level of α = 0.05.
Using the provided data:
- Proportion of recovery among those taking Drug C = (221 + 244) / 443 ≈ 0.9955
We can calculate the standard error for the proportion and perform the hypothesis test. I'll calculate the z-score and p-value for you:
Z = (0.9955 - 0.55) / √[0.55 * (1 - 0.55) / 443] ≈ 18.3841
The critical values for a two-tailed test at α = 0.05 are approximately ±1.96.
Since our calculated z-score (18.3841) is much greater than the critical value (1.96), we can reject the null hypothesis.
Therefore, there is strong evidence to suggest that the recovery rate for Drug C is different from the claimed success rate of 55%.
c. **Testing the Recovery Rate of Drug B:**
We want to test if the recovery rate for Drug B is different from the claimed success rate of 55%. We'll perform a two-tailed test at a significance level of α = 0.1.
Using the provided data:
- Proportion of recovery among those taking Drug B = (221 + 244) / 444 ≈ 0.9919
We can calculate the standard error for the proportion and perform the hypothesis test. I'll calculate the z-score and p-value for you:
Z = (0.9919 - 0.55) / √[0.55 * (1 - 0.55) / 444] ≈ 17.7503
The critical values for a two-tailed test at α = 0.1 are approximately ±1.645.
Since our calculated z-score (17.7503) is much greater than the critical value (1.645), we can reject the null hypothesis.
Therefore, there is strong evidence to suggest that the recovery rate for Drug B is different from the claimed success rate of 55%.
a. sedentary activities
b. flexibility activities
c. aerobic activities
d. lifestyle activities
Yoga fits the level two of the physical activity pyramid that works on flexibility.
Further Explanation:
The daily activity of an individual is regulated by the physical activity pyramid. The pyramid of physical activity differentiates the various kinds of exercises into different levels. It aids in attaining an individual a healthy life. To attain a disease free-life, an adult should do exercise for thirty minutes while children should do physical activity for an hour daily. It is distinguished into four different levels. The different levels are:
Learn More:
Answer Details:
Grade: High School
Subject: Health
Chapter: Fitness Program
Keywords:
Physical activity, strength, flexibility, yoga, stretching, lifestyle, aerobic exercise, walking, talking, games, pyramid.
B. Volunteering with a local youth group.
C. Both A and B
both a and b
they did not ask u if it was positive impact