MATHEMATICS MIDDLE SCHOOL

Given CDEFG ≌ HIJKL and CD = 12, DE = 13, EF = 10, FG = 11, and GC = 8, what is HI?

Answers

Answer 1
Answer: 12 b/c if cdefg is equivalent to hijkl then the length are equivalent to.

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A large truck is going down a hill at 60 miles per hour. The driver needs to begin slowing down by shifting the gears. The speed goes down by 10 miles per hour each time he downshifts. Which expression shows his speed after three shifts?60 + (3 × 10)


60 – (-10 × 3)


60 – 10


60 + (-10 × 3)

Answers

It would be D. 69 + ( - 10 x 3 ). Because here are the keywords. He was going DOWN (negative) at a hill. And he now needs to SLOW DOWN (negative) by shifting the gears. Then he speeds DOWN (negative) 10 miles PER hour. And it says, how much speed after 3 shifts.

Find the length of ED.

Answers

answer:x = 10 ed

x = 14 ac

                                     
52 I took the test yo boy know

Find the value of the expression: 5/(-1.5+9.5) + 0.4 (7+11) / -0.2 show your work

Answers

Answer:

The final answer is

-283/8

Step-by-step explanation:

Given the expression

5/(-1.5+9.5) + 0.4 (7+11) / -0.2

To solve this problem we need to break down its component in steps

Step one

First Let's solve the items in the bracket

5/8+ 0.4 (18) / -0.2

Secondly let's open up the bracket

5/8+7. 2/-0.2

Step two :

We can still solve for the second fraction by Dividing it accordingly

=5/8+(-36)

=5/8-36

Solving the fraction we have

Lcm= 8

=5-288/8

=-283/8

(5)/( (- 1.5 + 9.5)) + (0.4(7 + 11))/( - 0.2 ) \n = (5)/(8) + (0.4 * 18)/( - 0.2 ) \n = (5)/(8) + (7.2)/( - 0.2 ) \n = (5)/(8) - 36 \n = - (283)/(8)

A 1350 kg car travels at 12 m/s. What is it's kinetic energy

Answers

energy is always transformed from one form to another

energy is not created nor destroyed

so when a car starts moving the chemical potential energy of the car is converted to kinetic energy

kinetic energy is the energy that moving objects possess

kinetic energy formula is as follows

Kinetic energy = 1/2 mv²

where m - mass

v - velocity

substituting these values


K.E = 1/2 x 1350 kg x (12 m/s)²

= 1/2 x 1350 x 144 = 97200 J

the kinetic energy of the car is 97.2 kJ

Hello!

A 1350 kg car travels at 12 m/s. What is it's kinetic energy ?

We have the following data:  

m (mass) = 1350 kg  

v (velocity) = 12 m/s  

KE (kinetic Energy) = ? (in Joule)  

Formula to calculate kinetic energy:

\boxed{KE = (1)/(2) *m*v^2}

Solving:

KE = (1)/(2) *m*v^2

KE = (1)/(2) *1350*12^2

KE = (1)/(2) *1350*144

KE = (194400)/(2)

\boxed{\boxed{KE = 97200\:Joule}}\:or\:\boxed{\boxed{KE = 97.2\:kJ}}\Longleftarrow(kinetic\:energy)\:\:\:\:\:\:\bf\blue{\checkmark}

_______________________

\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

A regular hexagon has a perimeter of 12 X +60. Which expression represents the length of each side of the hexagon?

Answers

Divide 12x+60 by 6 because there are six sides to a hexagon and we are talking about perimeter. The length of each side will equal 2x+10.

-16 = 0.2b please show work

Answers

-16 = 0.2b

Divide 0.2 on both sides to isolate b.

-16 ÷ 0.2 = -80

-80 = b

b = -80. 
divide 0.2 to -16 and then you have your but to check if its right multiply 0.2 to the number you get.and the answer that you get is a negative
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