the carousel costs 5 tokens. The inequality
7x + 5y = 50 represents the possible ways
Marcus could use his tokens on the two rides.
Is the ordered pair (6, 3) a solution for the
problem situation?
Answer:
The ordered pair (6,3) can not be a solution for the problem situation.
Step-by-step explanation:
Marcus has total 50 tokens to spend at the carnival.
Now, given that the Ferris wheel costs 7 tokens and the carousel costs 5 tokens.
So, if Marcus play the Ferris wheel for x times and the carousel for y times, the total expenditure will be given by
7x + 5y = 50 ............ (1)
Now, the ordered pair (6,3) i.e. x = 6 and y = 3 does not satisfy the above relation equation (1).
So, the ordered pair (6,3) can not be a solution for the problem situation. (Answer)
first (shortest) side = x
second side = x + 5
third side = 2x - 5
the perimeter = 64 ft and is equal x + (x + 5) + (2x - 5)
x + x + 5 + 2x - 5 = 64
4x = 64 |:4
x = 16 ft
x + 5 = 16 + 5 = 21 ft
2x - 5 = 2(16) - 5 = 27 ft
Answer: 16ft, 21ft and 27ft.
The three equivalent ratios are 27/6, 45/10, and 36/8.
Given,
The ratio of right-handed students to left-handed students is 18:4.
We need to find three equivalentratios of 18:4.
A ratio is denoted by A:B.
If the ratios are equal we called it proportion.
Example:
2/4 = 16/32 = 6/12
2/4 = 1/2
16/32 = 2/4 = 1/2
6/12 = 1/2
2/4, 16/32, and 6/12 are equivalent ratios and they are in proportion.
We have,
18:4
It can be written as:
= 18/4
Reducing it to the smallest term.
= 2 x 9 / 2 x 2
= 9 / 2
So,
We can have,
27/6, 45/10, and 36/8 as our equivalentratios.
27/6 = 3 x 9 / 3 x 2 = 9/2
45/10 = 5 x 9 / 5 x 2 = 9/2
36/8 = 4 x 9 / 4 x 2 = 9/2
Thus the three equivalent ratios are 27/6, 45/10, and 36/8.
Learn more about ratios here:
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