With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s
Using the principles of free fall motion, it can be determined that a tennis ball dropped from a height of 1.16 meters would hit the ground with a velocity of 4.8 m/s.
The objective here is to calculate the initial velocity of the tennis ball just before it hits the ground. This is a physics question related to free fall motion. We will use the equation of motion, v^2 = u^2 + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration, and 's' is the distance. In our case, the initial velocity (u) is 0 because the ball is dropped, not thrown downwards.
The acceleration (a) is the acceleration due to gravity, which is -9.8 m/s² (it's negative because it acts downwards). The distance (s) will be the drop height, which is -1.16 m (it's negative because we're considering downwards as negative direction). Therefore, the equation becomes (v)^2 = 0 + 2*(-9.8 m/s²)*(-1.16 m). Solving this we get v = √(2*9.8*1.16) m/s = 4.8 m/s. So, the tennis ball hits the ground with a velocity of 4.8 m/s.
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Answer: 200 W
Explanation:
In physics, power is defined as the amount of work done divided by the time taken to do that work:
where W is the work done and t is the time.
In this problem, the work done is W=600 J, while the time taken is t=3 s. Substituting into the formula, we find the power:
Answer:
the answer is 3000
Explanation:
power=mass×gravity×height or (divided by /Time)
so 100kg×10×60m/20s
=60,000/20
=3000joule
if I am wrong correct me
B. a group of stars
C. an entire galaxy
D. one single planet
Answer:The day and night cycle would change bye 1.34 hours
Explanation: