Answer:
The distance travelled is 2.34*10^8 m.
Explanation:
The acceleration of the spacecraft is,
a=F/m
=391/7870 = 0.04968 m/s^2
The distance travelled,
d=v^2-v0^2/2a
=(4820)^2-(38)^2 / 2(0.04968)
=2.34*10^8 m.
force constant (spring constant) of the spring?
A) 39 N/m
B) 22 N/m
C) 46 N/m
D) 31 N/m