Answer: The star's outer layers drifts away.
Explanation: When a star starts running out of fuel the pressure in the core becomes very high which pushes the outer layers of the star.
A sun like star becomes a red giant and after throwing away the mass, the core contracts to becomes a white dwarf.
A massive star becomes super-giant and then the core becomes a neutron star or a black-hole.
Answer:
The answer is d
Explanation:
Sedimentary rocks are made when sand, mud and pebbles get laid down in layers.
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Question 7 options:
Their speeds are the same.
the object with the greater speed has greater kinetic energy
the object greater speed has the lower kinetic energy
the object with the smaller mass has the greater kinetic energy
Answer: Option (B) is the correct answer.
Explanation:
Kinetic energy is the energy due to the motion of an object.
Mathematically, K.E =
where m = mass
v = velocity
Therefore, an object whose velocity is more will have more kinetic energy.
Thus, we can conclude that out of the given options, the object with the greater speed has greater kinetic energy is true about their kinetic energy.
(2) The rate of the forward reaction must equal the rate of the reverse reaction.
(3) The concentration of the reactants must equal the concentration of the products.
(4) The potential energy of the reactants must equal the potential energy of the products.
Answer: The correct answer is Option 2.
Explanation:
Reversible reaction is defined as the reaction in which the products formed react together to give the reactants back. For general reversible chemical equation:
At equilibrium, the rate of forward reaction is equal to the rate of backward reaction.
Rate of forward reaction:
Rate of backward reaction:
At equilibrium, =
Thus, the correct answer is Option 2.
NOT 100% SURE
Thermal Energy..?
When I think of three states of matter I think of water as an example:
• Adding extreme heat to the liquid form of water can turn it into gas.
• Adding heat to ice can turn it into the liquid form of water.
• Freezing the liquid form of water can turn it into ice.
I would say temperature (thermal energy) has an effect of the different states of matter.
Answer:
There will be produced 66g of CO2 if 45g of glucose completely reacted with oxygen
Explanation:
Step 1 : Balance the formula
Oxidation of glucose can be shown in the following equation :
C6H12O6 + 6 O2 → 6 CO2 + 6H2O
This means that for 1 mole glucose that react there will react 6 moles of O2, to form 6 moles of CO2 and 6 moles of H2O
Step 2: Calculating moles
mole glucose = 45g / Molar mass glucose
⇒ Molar mass = 6*12 + 12*1 + 6*16 = 72 + 12 + 96 = 180g/mole
⇒ mole glucose = 45g / 180g/mole
⇒mole glucose = 0.25 mole
Since 1 mole of glucose is used to form 6 moles of CO2
0.25 mole of glucose is used to form 1.5 moles of CO2
Step 3 : Calculating mass of Carbon dioxide
Mass of CO2 = 1.5 moles of CO2 * 44 g/mole
mass of CO2 = 66g
There will be produced 66g of CO2 if 45g of glucose completely reacted with oxygen
If 45g of glucose reacts with oxygen, 66.015 grams of carbon dioxide would be produced. This calculation is based on converting the mass of glucose to moles, using the stoichiometry of the balanced chemical equation, and then calculating the mass of CO2 produced.
When glucose (which has the chemical formula C6H12O6) is consumed, it reacts with oxygen to produce carbon dioxide, water, and energy. The chemical equation for this reaction is C6H12O6 + 6 O2 → 6 CO2 + 6 H2O. Given that 45g of C6H12O6 completely reacts with oxygen, we need to calculate the mass of carbon dioxide produced from this reaction.
To do this, we first need to determine the molar mass of glucose, which is 180.16 g/mol. This means that 1 mole of glucose weighs 180.16 grams. We can then find out how many moles of glucose 45g represents by dividing 45g by 180.16 g/mol, which gives us 0.25 mol of glucose.
According to the chemical equation, 1 mole of glucose produces 6 moles of CO2. Therefore, 0.25 moles of glucose would produce 0.25 × 6 = 1.5 moles of CO2. The molar mass of CO2 is 44.01 g/mol, so the mass of CO2 produced by 0.25 moles of glucose is 1.5 moles × 44.01 g/mol, resulting in 66.015 grams of CO2. So, if 45g of C6H12O6 completely reacted with oxygen, 66.015 grams of CO2 would be produced.