The area of the composite figure is 57 square units.
The area of a triangle is the half of the product of the base and the height of the triangle.
The area of a square is the square of the side length of the square.
The area of a trapezoid is the half of the product of the sum of the parallel sides and the height of it.
Given, the base of the triangle is 4 units and height is 3 units.
Therefore, the area of the triangle is
square units
square units
The square has a side length of 4 units.
Therefore, the area of the square is
square units
square units
The trapezoid has a height of 5 units and two parallel sides of 6 units and 8 units.
Therefore, the area of the trapezoid is
× (sum of the parallel sides)
square units
square units
Therefore, the area of the composite figure
square units
= 57 square units
Learn more about the area of a triangle, square and trapezoid here: brainly.com/question/15880803
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Answer by JKismyhusbandbae: The answer is 49.
You wanna calculate the triangle and trapezoid and the square separately and add all the them together.
A.
B.
C.
D.
Answer:
Step-by-step explanation:
To find the number of child and adult tickets sold, we can use algebraic equations. Let's assume the number of child tickets sold is 'c' and the number of adult tickets sold is 'a'.
Given information:
Cost of child ticket: $6
Cost of adult ticket: $10
Total ticket sales: $600
1. Set up the equation for the total ticket sales:
6c + 10a = 600
2. We need to find a combination of 'c' and 'a' that satisfies this equation.
- Option 1: Let's assume all tickets sold were child tickets.
In this case, the equation becomes:
6c + 10(0) = 600
Simplifying, we get:
6c = 600
Solving for 'c':
c = 100
So, if all tickets were child tickets, 100 child tickets were sold.
- Option 2: Let's assume all tickets sold were adult tickets.
In this case, the equation becomes:
6(0) + 10a = 600
Simplifying, we get:
10a = 600
Solving for 'a':
a = 60
So, if all tickets were adult tickets, 60 adult tickets were sold.
- Option 3: Let's assume there were a combination of child and adult tickets sold.
We can try different values for 'c' and solve for 'a'.
For example, if we assume 'c' to be 50, the equation becomes:
6(50) + 10a = 600
Simplifying, we get:
300 + 10a = 600
Solving for 'a':
10a = 300
a = 30
So, if 50 child tickets and 30 adult tickets were sold, the equation is satisfied.
Therefore, there are multiple possible combinations of child and adult tickets sold that could result in $600 in ticket sales. The options are:
- 100 child tickets
- 60 adult tickets
- 50 child tickets and 30 adult tickets.
bananas are there?
We know that the ratio of apples to bananas is 2 to 3, which can also be written as 2/3.
Let's use a proportion to solve for the number of bananas:
2/3 = 12/x
Here, x represents the number of bananas in the bowl.
To solve for x, we can cross-multiply:
2x = 3 * 12
2x = 36
x = 18
Therefore, there are 18 bananas in the bowl.
Answer:
18 bananas
Step-by-step explanation:
for every 2 apples, there are 3 bananas.
So, if there are 12 apples then the original ratio of number of apples is being multiplied by 6
To prove this, 2 is the original ratio of apples and when 2 is multiplied by 6, you get 12 apples
To ensure the ratio of apples to bananas is the same, you multiply the original ratio of bananas by 3 as well. This leaves us with 18 bananas for every 12 apples (3*6 = 18)
To check if you are correct, you divide both the number of apples and the number of bananas by 6 and you get the original ratio, 2 to 3.
The ratio is essentially the same throughout except when you increase it by a constant ratio, it is no longer simplified but it is the same.
I tried explaining this the best I could and I really hope this made sense and helped!
Answer:
88
Step-by-step explanation:because you just do that math