The minimum value of f is f×3=-5 and f×1=2
The question provides two equations involving the variable f. By isolating f in these equations, we derive two possible values for f. The minimum value for f is the smaller of these two derived values, which is -5/3.
To solve this we can use the principle that if two different values of f multiply with different numbers to equal different constants, we can set up a system of equations to find those values of f.
The given equations are f×3=-5 and f×1=2. Let's denote f×1 as f₁ and f×3 as f₂.
So, the minimum value of f, that is f_min would be the smaller of f₁ and f₂. As -5/3 is smaller than 2, f_min = -5/3.
#SPJ2
Answer: The first or the second point (- 2, - 3) or (- 2, 1)
Step-by-step explanation:
Ok, a relation (x, y) is a function only if, for each value x in the domain, we have only one value y in the range such that:
f(x) = y.
Here we have the pairs:
(- 2, - 3), (- 2, 1), (- 4, 3), (0, 4), (1, 1), and (2, 3).
Here, for the value x = -2, we have two different values of y.
y = 1 and y = 3.
So this is not a function, then if we want that this relation becomes a function, we must remove the first or the second point.
Answer:
I think B
Step-by-step explanation:
x=-17 17
X=-2+25
x=-12 13
Answer:
it would be the last answer
Step-by-step explanation: