STP means standard temperature and pressure at 0°C (273K) and 1 atm (atmosphere). The density of the unknown gas is 0.63 gram per liter. The deal gas equation is PV = nRT. The n is the numer of moles and can be represented as mass of the gas, m, divided by the molar mass, c. so we have,
PV = nRT
PV = (m/c)RT
Since the density is d = m/V
Pc = (m/V)RT
Pc = dRT
c = drT/P
substitute the values into the equation,
c = [(0.63g/L)(0.08206 L-atm/mol-K)(273K)]/(1atm)
c = 14.11 g/mol
Answer is: the sample is 232 years old.
Take 100 atoms:
After first half-life: 50% · 100 ÷ 100% = 50.
After second half-life: 0.5 · 50 = 25.
After third half-life: 0.5 · 25 = 12.5.
After fourth half-life: 0.5 · 12.5 = 6.25.
6.25 ÷ 100 · 100% = 6.25%.
4 half-lives will it take before only about 6.25% of the original sample remains.
t = 4 · 58 y.
t = 232 y.
versus
2 H2 + O2 -> 2 H2O?
They are both balanced chemical equations.
The two reactions are equivalent.
The laws of thermodynamics apply to both.
Conservation of mass applies to both.
Hybridization of orbitals is the concept of incorporation atomic orbitals into new hybrid orbitals appropriate for the pairing of electrons to form chemical bonds in valence bond theory.
B. 2, 8, 18, 32
C. 8, 8, 8, 8
b. solvent.
c. acid.
d. base.