Which of the following is not an acid-base neutralization reaction? (3 points)NH3 + HCl yields NH4Cl
NaOH + CH3COOH yields Na CH3COO + H2O
2HNO3 + Ca(OH)2 yields Ca(NO3)2 + 2H2O
H2SO4 + 2NaCl yields 2HCl + Na2SO4
Answers
H2SO4 + 2NaCl yields 2HCl + Na2SO4
is the correct answer...
because neutralisation reaction yields salt n water but here acid is produced so the solution isn't neutralized......
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An 8.5 g ice cube is placed into 255g of water. Calculate the temperature change of water when the ice melts
Are these answers correct?1. A gas occupies 30 L at 760 mm Hg. What is its volume at 350 mm Hg? P1*V1 = P2*V2 760 mm Hg *30 L = 350 mm Hg * V2V2 = 22800 mm Hg*L/350 mm HgV2 = about 65.14 L2. A gas occupies 500 mL at 1 atm. What is its pressure if the volume becomes 1500 mL?P1*V1 = P2*V21 atm*500 mL = P2*1500 mL500 atm*mL/1500 mL = P2P2 = 1/3 atm3. If a gas occupies 250 mL at 25°C, what will its volume be at 57°C? 25°C + 273 = 298°K; 57°C + 273 = 330°KV1/T1 = V2/T2250 mL/298°K = V2/330°K0.84 mL/k*330°K = V2V2 = about 276.85 mL4. What was the original temperature of a 2 L sample of gas if it initially had the volume 5 L at 27°C? 27°C + 273 = 298°KV1/T1 = V2/T25 L/298°K = 2 L/T22 L/(0.017 L/K)= T2T2 = 119.2°K = -153.8°C 5. At what pressure would 100 mL of a gas be found if it began at 500 mL at 2.5 atm?P1*V1 = P2*V2 2.5 atm*500 mL = P2*100 mL125 atm*mL/100 mL = P2P2 = 1.25 atm6. What is the volume of a gas at 275 mm Hg if it occupied 750 mL at 1000 mm Hg?P1*V1 = P2*V21000 mm Hg*750 mL = 275 mm Hg*V2750000 mm Hg*mL/275 mm Hg = V2V2 = about 2727. 27 mL7. A gas occupies 60 L at 250°K and 1 atm. What is its volume at 250°C and 1.5 atm?250°C + 273 = 523°KP1*V1/T1 = P2*V2/T21 atm*60 L/250°K = 1.5 atm*V2/523°K0.24 (atm*L/K)*523°K = 1.5 atm*V2125.52 (atm*L)/1.5 atm = V2V2 = 83.68 L8. What is the final temperature in Celsius of a gas occupying 3.25 L at 750 mm Hg if it occupied 2250 mL at 37°C and 600 mm Hg? 37°C + 273 = 310°K; 2250 mL = 2.25 LP1*V1/T1 = P2*V2/T2600 mm Hg*2.25 L/310°K = 750 mm Hg*3.25 L/T22437.35 mm Hg*L/ (4.35 mm Hg*L/K) = T2T2 = 559.69°KT2 = about 286.69°C
What is happening in this picture? Look at the food colouring and explain using the following terms: solute, solvent, dissolving, homogenous.
Stoichiometry! Please note:- Use 6.022x1023 for avogadro’s number- Ignore sig figs and do not round the final answer.- Keep it to 1 decimal place.
Answers
The mass of one cubic meter of gold is 19,300 kilograms.
We can use the specified density and the following formula to determine the mass of one cubic meter of gold:
Mass = Density × Volume
Given:
Density of gold = 19.3 g/cm³
Remember that when converting from cubic centimeters to cubic meters, 1 cubic meter is equal to 1,000,000 cubic centimeters.
Density = Mass / Volume
Mass = Density × Volume
Volume = 1 cubic meter = 1,000,000 cubic centimeters
Density = 19.3 g/cm³
Mass (grams) = Density × Volume = 19.3 g/cm³ × 1,000,000 cm³ = 19,300,000 g
For converting grams to kilograms, divide by 1000:
Mass (kilograms) = 19,300,000 g / 1000 = 19,300 kg
Therefore, the mass of one cubic meter of gold is 19,300 kilograms.
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Answer:
Explanation:
Question:
Gold has a density of
19.3
g
/
c
m
3
.
What is the mass, in kilograms, of one cubic meter of gold?
Density:
The density of an object is a quantity derived from the relation between mass (fundamental quantity) and volume (derived quantity). No matter the size of the object, its density will be the same because it is a constant property that is only varied when changing the mass or volume of the object. There are other factors that affect density such as temperature and pressure.
Data:
Volume:
V
=
1
m
3
Density:
ρ
=
19.3
g
c
m
3
Equation:
The equation to find the mass of the gold is given...
See full answer below.
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Density: Definition, Formula & Practice Problems
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Chapter 1 / Lesson 10
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Answers
Final answer:
The magnification of Robert's drawing of a wood louse can be obtained by dividing the size of the drawing (5mm) by the actual size of the wood louse (0.4mm). This gives a magnification of 12.5 times.
Explanation:
The magnification of a drawing can be calculated using the method 'Image size/Actual size'. In this question, Robert's drawing is of a size 5mm while the actual size of the wood louse is 0.4mm. Substituting these values into the formula, you would get 5mm/0.4mm which equates to a magnification of 12.5 times.
The magnification of Robert's drawing of a wood louse can be calculated by dividing the size of the drawing by the actual size, resulting in a magnification of 12.5.
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Answer:
Magnification is the number of times larger an image is compared with the real size of the object.
Magnification = Image / Actual = 5/0.4 =12.5
Explanation:
Answers
b. two significant figures.
c. three significant figures.
d. five significant figures.
Answers
a. One significant figure:
- Expressing 385,500 as 3.9 × 10^5 hours (rounded to one significant figure).
b. Two significant figures:
- Expressing 385,500 as 3.9 × 10^5 hours (rounded to two significant figures).
c. Three significant figures:
- Expressing 385,500 as 3.86 × 10^5 hours (rounded to three significant figures).
d. Five significant figures:
- Expressing 385,500 as 3.8550 × 10^5 hours (rounded to five significant figures).
Keep in mind that the exponential notation represents the same value but with the specified number of significant figures.
Answers
Answer:
The answer is
3.54 mL
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 9.38 g
density = 2.65 g/cm³
The volume of the quartz is
We have the final answer as
3.54 mL
Hope this helps you
Answers
Answer:
freezing
Explanation: