The coordinates of point M, the midpoint of line segment AB, are (0, -2.5).
The midpoint formula is expressed as;
M = ( (x₁+x₂)/2, (y₁+y₂)/2 )
Given the parameter:
Point A (6,-7): x₁ = 6 and y₁ = -7
Point B (-6,2): x₂ = -6 and y₂ = 2
Plug the coordinates into the above formula and simplify:
Therefore, the coordinates of the midpoint M are (0,-2.5).
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The midpoint of segment AB is (0, 2.5).
2x+3y=sinx
h(x) = x - 4
h(x) = 2x
h(x) = IX
Answer:
Step-by-step explanation:
(1) = f(x) = 4x
(2) h(x) = x + 4
y = x + 4
Replace x with y and vice versa:
x = y + 4
And then solve for 'y':
y = x - 4
(3) h(x) = x - 4
y = x - 4
x = y - 4
y = x + 4
(4) h(x) = 2x
y = 2x
x = 2y
y =