Hope this is what you need
Answer:
I am not sure of the equation but I interpreted it as x^2a^2+3xa^2+2a^2
Step-by-step explanation:
X^2a^2+3xa^2+2a^2
1. a^2 (x^2+3x+2)
2.a^2(x^2+2x+x+2)
3. a^2(x(x+2)+x+2)
4. a^2(x+2)(x+1)
Incorrect; Only two isosceles triangles can form a rhombus.
On a coordinate plane, a parabola opens down. It goes through (negative 4, 0), has a vertex at (negative 1. 75, 6.2), and goes through (1, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 1, 0), has a vertex at (1. 75, negative 6.2), and goes through (4, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 4, 0), has a vertex at (negative 1. 75, negative 6.2), and goes through (1, 0).
Answer:
None of the above
Step-by-step explanation:
See the attachment for x-intercepts and vertex coordinates. These coordinates do not match any of the answer choices.
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The closest choice is the last one. It has the direction of opening and the intercepts correct, but the vertex coordinates wrong.
We can write the graph of f(x) = (x - 1)(x + 4) as, "On a coordinate plane, a parabola opens up. It goes through (-4, 0), has a vertex at (-1.5, -6.25), and goes through (1, 0)."
A parabola is a plane curve created by a moving point whose distance from a stationary point equals its distance from a fixed-line.
In the question, we are given an equation of f(x) = (x - 1)(x + 4), and are asked to identify its graph.
The given equation is of a parabola in the intercept form f(x) = a(x - p)(x - q), which opens up if a > 0 and opens down if a < 0, and which has a vertex at the point , and passes through the point (p, 0) and (q, 0).
Comparing the equation f(x) = (x - 1)(x + 4) to f(x) = a(x - p)(x - q), we get
a = 1, p = 1, q = -4.
Since, a > 0 (a = 1), we can say that it opens up.
Now, we calculate (p + q)/2 = (1 - 4)/2 = -1.5
f((p + q)/2) = f(1.5) = (-1.5 - 1)(-1.5 + 4) = (-2.5)(2.5) = -6.25.
Thus, the vertex is at point (-1.5, -6.25).
Also, the equation passes through the points (-4, 0) and (1, 0).
∴ We can write the graph of f(x) = (x - 1)(x + 4) as, "On a coordinate plane, a parabola opens up. It goes through (-4, 0), has a vertex at (-1.5, -6.25), and goes through (1, 0)."
Learn more about a Parabola at
#SPJ2
Here is your equation:
In this equation, you're looking for the value of d alone. That means you would have to move everything next to the variable to the other side. You can do that by doing the opposite of what's being done to it.
In this equation, 5d is being subtracted by 10(-10). The opposite of that is adding 10(+10). You would have to add 10 to both sides, since -10 and +10 cancel out each other.
The first thing you are going to do is add 10 to both sides.
Now you're left with the equation 5d=30. Remember that you're looking for d alone. In the current equation, d is being multiplied by 5(5d ⇒ 5 × d). Again, you're going to do the opposite of what's being done to it. The opposite of multiplying is dividing, therefore, you're going to divide both sides by 5, since the 5 divided by 5 is 1, which cancels out the 5.
Divide both sides by 5.
That means the answer to your equation is d = 6.
Answer:
d = 6
Step-by-step explanation:
Let us follow these steps to make d the subject.
First, add 10 to both sides.
5d - 10 = 20
5d = 10+ 20
5d = 30
Divide both sides by 5.
d = 6