Nina walked 3.7 miles everyday for one month how many miles in all did she walk in 31 days

Answers

Answer 1

Answer: Nina walked 114.7 miles in 31 days. All you have to do is multiply 3.7 by 31

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Simplify 16/3(6/8b+9/2).

Write in simplest form.

Answers

3/8 = 0.37500
hope its right...!!!!!

16/3(6/8b+9/2) Final result : 4 • (b + 6)

Step by step solution :Step 1 : 9 Simplify — 2 Equation at the end of step 1 : 16 6 9 —— • ((— • b) + —) 3 8 2Step 2 : 3 Simplify — 4 Equation at the end of step 2 : 16 3 9 —— • ((— • b) + —) 3 4 2 Step 3 :Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

      The left denominator is :       4

      The right denominator is :       2

        Number of times each prime factor
        appears in the factorization of: Prime
Factor  Left
Denominator  Right
Denominator  L.C.M = Max
{Left,Right} 2212 Product of all
Prime Factors 424

Least Common Multiple:
4

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

    Denote the Least Common Multiple by  L.C.M
    Denote the Left Multiplier by  Left_M
    Denote the Right Multiplier by  Right_M
    Denote the Left Deniminator by  L_Deno
    Denote the Right Multiplier by  R_Deno

   Left_M = L.C.M / L_Deno = 1

   Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

3.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respectiveMultiplier.

L. Mult. • L. Num. 3b —————————————————— = —— L.C.M 4 R. Mult. • R. Num. 9 • 2 —————————————————— = ————— L.C.M 4 Adding fractions that have a common denominator :

3.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3b + 9 • 2 3b + 18 —————————— = ——————— 4 4 Equation at the end of step 3 : 16 (3b + 18) —— • ————————— 3 4 Step 4 : 16 Simplify —— 3 Equation at the end of step 4 : 16 (3b + 18) —— • ————————— 3 4 Step 5 :Step 6 :Pulling out like terms :

6.1 Pull out like factors :

3b + 18 = 3 • (b + 6)

Final result : 4 • (b + 6)

Helena needs 3.5 cups of flour per loaf of bread and 2.5 cups of flour per batch of muffins. She also needs 0.75 cup of sugar per loaf of bread and 0.75 cup of sugar per batch of muffins. Helena has 17 cups of flour and 4.5 cups of sugar available for baking.

Answers

From the given data, we can generate two equations with two unknowns.

We let x = number of loaves of bread
y = number of batches of muffins

For the equation of the flour requirement:
17 = 3.5x + 2.5y

For the equation of the sugar requirement:
4.5 = 0.75x + 0.75y

We evaluate the solutions by manipulating one of the equations into terms of the other. We use the first equation.We write x in terms of y.

x = (4.5/0.75) - y

Substitute the third equation to the second equation.

17 = (3.5((4.5/0.75)-y)) + 2.5y

Evaluating y and x, we have,

y = 4 and x = 2

Thus, from the amounts she has in hand, she can make 4 loaves of bread and 2 batches of muffins.

Answer:

The Correct answer is c.

Step-by-step explanation:

Hope this helps!!!!:)

What is the inequality of 0.3(0.3x+0.8)<-0.3

Answers

$0.3(0.3x+0.8)<-0.3\ /:0.3\n\n0.3(0.3x+0.8):0.3<-0.3:0.3\n\n0.3x+0.8<-1\n\n0.3x<-1-0.8\n\n0.3x<-1.8\ /:0.3\n\nx<- (1.8)/(0.3) \n\nx<- (18)/(3) \n\nx<-6\ \ \ \ \Leftrightarrow\ \ \ x\in(-\infty;\ -6)$

Select all the choices that decision makers could use marginal analysis for to make effective decisions. a.) producing another car
b.) consuming one more slice of pizza
c.) adding a machine to the factory
d.) buying an extra concert ticket

Answers

marginal anylasis is thinking at the margin or when right before you will make the choice

A.
producing another car
depends on how fast you can product, I don't think it is very fast, so no

B.
this is marginal thinking, you already have the pizza in front of you

c. same as A, not

D. you are already buying one

B and D

The answer to your question is B and D

Civil engineer wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He assumes that each car is 14 feet long, travels at speed S, and follows the car in front of it at a safe distance for that speed. He finds that the number N of cars that can pass a given spot per minute is modeled by the function N=(89s)/(14+14(s/17)^2))

At what speed can the greatest number of cars travel safely on that road? Assume that the maximum possible speed of a car is less than 300.

Answers

$N(s)= (89s)/(14+14( (s)/(17))^2 )\n\nN'(s)= ((89s)/(14+14( (s)/(17))^2 ) )'= (89* 14(1+( (s)/(17))^2)-89s* (28)/(17) )/(14^2(1+( (s)/(17))^2)) \n\nN'(s)=0\n\n89* 14(1+( (s)/(17))^2)-89s* (28)/(17)=0\n\n1+( (s)/(17))^2- (2s)/(17) =0\n\n289+s^2-34s=0\n\ns^2-34s+289=0\n\n(s-17)^2=0\n\ns=17$

What is the square root of 100? Check all that apply. -50i 10i-10i 50i

Answers

The square root of 100 equals 10 because 10 times 10 equals 100

$10$ × $10=100$ -> $√(100)=10$

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Divide 72 kg in a ratio of 1:3:5

Need help with this help plz

For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0. graph of f of x equals 0.5 to the x power, minus 6.

Does the equation x2 - 6x + y2 - 6y = -9 intersect the y-axis? A) Yes, it intersects the y-axis at (0, 3). B) Yes, it intersects the y-axis at (3, 0). C) No, because the circle is entirely in the first quadrant. D) No, because the center is a (3, 3) and the radius is 9.