Jackson weighed 6 pounds 3 ounces when he was born. When he was 4 weeks old, he weighed 128 ounces. How much weight did jacskon gain in those 4 weeks?

Answers

Answer 1

Answer: 1 pound = 16 ounces
16×6=?

128- ?+3

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Wright an expression for the calculation 4 times the difference of 10 and 8 minus 3

Answers

It would havs to be four times two minus three.

Is there several ways to list the partial products of 35x7

Answers

Not really

30x7=210
5x7=35

yes there is one way i am learning at school in my class room commutive property 35×7=210, 30+70=100, 3×7=21, 21÷3=7

A catering service offers 9 appetizers 8 main courses and 3 desserts. A customer is to select 6 appetizers 5 main courses and 2 desserts for a banquet. In how many ways can this be done?

Answers

Answer: 14112

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Explanation:

We'll be using the n C r combination function. To make the notation a bit easier to deal with, I will write "C(n,r)" instead of "n C r".

The formula is

C(n,r) = (n!)/(r!*(n-r)!)

where the exclamation marks represent factorials.

A factorial is where you start with a positive integer, and count down to 1 multiplying all along the way.

Examples:

5! = 5*4*3*2*1

8! = 8*7*6*5*4*3*2*1 = 120

Note how the string "5*4*3*2*1" is in both 5! and 8!

We can say 8! = 8*7*6*5!

Because we can replace the "5!" at the end with "5*4*3*2*1" later if we wanted. This strategy is used to help find a shortcut to simplification.

--------------------------

We have n = 9 appetizers and r = 6 items we can select from this pool.

C(n,r) = (n!)/(r!*(n-r)!)

C(9,6) = (9!)/(6!*(9-6)!)

C(9,6) = (9!)/(6!*3!)

C(9,6) = (9*8*7*6!)/(6!*3*2*1)

C(9,6) = (9*8*7)/(3*2*1) .... the "6!" terms canceled out

C(9,6) = 504/6

C(9,6) = 84

There are 84 ways to choose six appetizers from the pool of nine available

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Repeat those steps for the main courses. Use n = 8 and r = 5 this time.

C(n,r) = (n!)/(r!(n-r)!)

C(8,5) = (8!)/(5!*(8-5)!)

C(8,5) = (8!)/(5!*3!)

C(8,5) = (8*7*6*5!)/(5!*3*2*1)

C(8,5) = (8*7*6)/(3*2*1)

C(8,5) = (336)/(6)

C(8,5) = 56

There are 56 ways to choose five main course meals from the pool of eight available

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Then do the same for the desserts. Use n = 3 and r = 2.

C(n,r) = (n!)/(r!(n-r)!)

C(3,2) = (3!)/(2!*(3-2)!)

C(3,2) = (3!)/(2!*1!)

C(3,2) = (3*2*1)/(2*1*1)

C(3,2) = 6/3

C(3,2) = 3

There are 3 ways to choose two desserts from the pool of three available

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The last step is to multiply all these results:

84*56*3 = 14112

This is the number of ways to select all of the items given the restrictions listed. The order does not matter.

Which expression is equivalent to 16a - 18b + 20a

Answers

(16a+20a)-18b
=36a-18b

write a word problem that can be solved by ordering three decimals to thousandths. include a solution

Answers

Mary, Anne, and Rose decided to race their three pet snails, Anthony, James, and Thomas to see which was fastest. Anthony finished in 23.38 minutes. James finished in 23.65 minutes. Thomas finished in 23.13 minutes. Order the finish times from least amount of time to greatest to see which snail was the winner of this very intense and serious race.
23.12, 23.38, 23.65

Final answer:

An example of a word problem that can be solved by ordering three decimals to thousandths is determining the order in which three items were purchased based on their prices.

Explanation:

An example of a word problem that can be solved by ordering three decimals to thousandths is:

John bought 3 different items from a store. The prices of the items were $2.345, $2.450, and $2.400 respectively. In what order did John purchase the items from least expensive to most expensive?

To solve this problem, we can order the decimals from least to greatest by looking at the thousandths place. The correct order is $2.350, $2.400, and $2.450.