Answer : The correct option is, 318.1 J
Solution :
The given chemical reaction will be,
In this reaction, X and Y are the reactants and W and Z are the products.
As we know that the energy remains conserved during the chemical reaction.
So,
Sum of energy of product = Sum of energy of reactant
Therefore, the amount of chemical energy of product Z contain will be, 318.1 J
Answer:
318.1 J
Explanation:
The reaction given is:
X + Y → W + Z
The chemical energy of the reaction (ΔU), is the variation of the chemical energy, so is the chemical energy of the products (UW and UZ) less the chemical energy of the reactants (UX and UY).
If the reaction loses the chemical energy, it must be negative, and the chemical energy that a substance contains, is positive.
ΔU = (UW + UZ) - (UX + UY)
-111.6 = (41.9 + UZ) - (199.3 +272.3)
-111.6 = 41.9 + UZ - 471.6
- UZ = - 429.27 + 111.6
-UZ = - 318.1
UZ = 318.1 J
1s 22s 22p1
1s22s22p4
1s 22s 2p2
1s 22s 22p2
Answer:
The answer to your question is: d
Explanation:
Electron configuration of Carbon.
Atomic number of carbon = 6
a) 1s²2s²2p¹ Number of electrons = 5, This is the electron configuration of Boron.
b) 1s²2s²2p⁴ Number of electrons = 8. This is the electron configuration of oxygen.
c) 1s²2s²p² Number of electrons = 6. This is the electron configuration of carbon. But I think is lacking a number two before p.
d) 1s²2s²2p² Number of electrons 6, This is the correct electron configuration of carbon.
MgO + CO2
Answer : The product formed in the combination reaction is, magnesium carbonate,
Explanation :
Combination reaction : It is a chemical reaction in which multiple substances or reactants combine to form a single product.
The balanced chemical reaction will be,
This reaction is a combination reaction in which the magnesium oxide react with the carbon dioxide to give magnesium carbonate as a product.
Hence, the product formed in the combination reaction is, magnesium carbonate,
a) in this we are diluting a stock solution, so we can use the dilution formula
c1v1 = c2v2
where c1 is concentration and v1 is volume of the stock solution
c2 is concentration and v2 is volume of the diluted solution to be prepared
substituting the values
6.0 M x V = 0.500 M x 110 mL
V = 9.17 mL
9.17 mL of the stock solution should be taken and diluted upto 110 mL to prepare the 0.500 M solution
b)
In this question we are given the volume taken from the stock solution , we have to find the concentration of the diluted solution
again we use the dilution formula, c1v1 = c2v2
substituting the values
6.0 M x 10.0 mL = C x 250 mL
C = 0.24 M
the concentration of diluted solution is 0.24 M
To prepare 110 ml of 0.500 M HNO3 from a 6.0 M HNO3 solution, 9.17 ml of the stock solution would have to be used. If 10.0 ml of the stock solution is diluted to a final volume of 0.250 L, the concentration of the diluted solution will be 0.24 M.
(a) In order to prepare 110 ml of 0.500 M HNO3 from a 6.0 M HNO3 solution, we have to use the formula M1V1 = M2V2 where M and V are the molarity and volume respectively. Here, the M1 and V1 are the molarity and volume of the stock solution and M2 and V2 are the molarity and volume of the diluted solution. Filling in known values, 6.0M * V1 = 0.500M * 110ml. Solving for V1, we get V1 = (0.500 M * 110 ml) / 6.0 M = 9.17 ml. So, you would have to use 9.17 ml of the stock solution.
(b) The diluted solution's molarity is calculated using the same formula as before. Substituting the known values 6.0M * 10.0 ml = M2 * 0.250 L, rearrange the formula to get M2= (6.0M * 10.0 ml) / 0.250 L = 0.24 M or 240 mM. Therefore, the concentration of the diluted solution is 0.24 M.
#SPJ11
metal and nonmetal
metalloid and nonmetal
two metals
Answer: The correct answer is metal and non-metal.
Explanation:
Elements are mainly divided into 3 classes in the periodic table.
1.) Metals: The element which lie on the left side of the periodic table are mainly metals. These elements loose electron easily and form positively charged species. These elements are present in the highest proportion in the periodic table.
2.) Non-metals: The elements which lie on the right side of the periodic table are considered as non-metals. These elements gain electrons easily and form negatively charged species.
3.) Metalloids: These lie between metals and non-metals and show the properties of both metals and non-metals.
Copper lie in the period 4 and group 11 of the periodic table and it can easily loose electron and hence, it is considered as a metal.
Chlorine lie in the period 3 and group 17 of the periodic table and it can easily gain electron and hence, considered as a non-metal.
Therefore, the correct answer is metal and non-metal.
The three states of matter are solid, liquid and gas phase. The solid has a more definite shape and volume. The particles are locked into place. It cannot be further compressed due to the bond that exists between the molecules. The kinetic energy of the molecules is close to none because the molecules are so close and so compact with each other. For liquids, it has a medium shape and volume. The particles can move or slide past each other due to the small space available for movement. It cannot be compressed further due to the repulsive forces that acts between them. The kinetic energy is medium. For gases, it has no shape and volume because the particles can move freely from one other. Their collisions are rare due to the distance between them. The kinetic energy of the molecules is high because there is room for movement. It can be compressed easily.