Answer:
Distance traveled by bicyclist traveling west = 15 miles
Step-by-step explanation:
Two bicyclists leave the center of town at the same time. One heads due north and the other heads due west. Later, the two cyclists are exactly 25 mi apart. The cyclist headed north has traveled 5 mi farther than the cyclist going west.
These two cyclists travel at angle 90°
Relative displacement can be calculated using Pythagoras theorem.
Let d be the distance traveled by bicyclist traveling west
Distance traveled by bicyclist traveling north = d + 5
Negative displacement is not possible.
Hence d = 15 miles
Distance traveled by bicyclist traveling west = d = 15 miles
Answer:c,d,a,d
Step-by-step explanation:
Answer:
I can't see it redo it so I can answer
Answer:
Step-by-step explanation:
Let a represent the length of board a.
Let y represent the length of board b.
The total length of both is 28 feet. This means that
a + b = 28
Board b is at least 5 feet longer than board a. This means that
b ≥ a + 5
The difference between both boards is not more than 12 feet. This means that
b - a < 12
Substituting a = 28 - b into b ≥ a + 5, it becomes.
b ≥ 28 - b + 5
b ≥ 28 - b + 5
2b ≥ 28
b ≥33/2
b ≥ 16.5
16.5 - a < 12
4.5 < a
a > 4.5
The possible lengths of board a is
8 to 11.5 feet
The possible lengths of board b is
16.5 to 20 feet
100 98
100 95
100 93
95 91
95 88
92 82
92 78
88 78
85 65
75 60
Putting the numbers in order;
Mid-term numbers: 100 100 100 95 95 92 92 88 85 75
Median = (95 + 92) / 2 = 93.5
First quarter = Q1 = 100 100 100 95
Median of first quarter = (100 + 100) / 2 = 100
Third quarter = Q3 = 92 88 85 75
Median of third quarter = (88 + 85) / 2 = 86.5
Interquartile range (IQR) can be calculated bysubtracting Q3 from Q1;
IQR of mid-term = 86.5 – 100 = -13.5
Now putting the final term numbers in order;
Final-term numbers: 98 95 93 91 88 82 78 78 65 60
Median = (88 + 82) / 2 = 85
First quarter = Q1 = 98 95 91 88
Median of first quarter = (95 + 91) / 2 = 93
Third quarter = Q3 = 78 78 65 60
Median of third quarter = (78 + 65) / 2 = 71.5
Interquartile range (IQR) can be calculated bysubtracting Q3 from Q1;
IQR of final-term = 71.5 – 93 = -21.5
Thus the IQR of mid-term is the largest.