A park is in the shape of a rectangle 2 miles long and 1.5 miles wide. How much shorter if you walk diaganolly across the park rather than along two sides?

Answers

Answer 1

Answer: You can answer this by using Pythagoras theorem. Okay, let me draw this first.

2 miles
V
________________________
| |
| |
| | << 1.5 miles
|_______________________|

^ Assume this is the rectangle. The long side is 2 miles while the shorter side is 1.5 miles.

So, to get the shortest distance, let's cut out a triangle from the rectangle.

    /|
       / |
/ |
What we want to find is this one > / | << 2 miles
   / |
  /______|
   ^ 1.5 miles (I know the size is not logical,but imagine   it please)

So to get the diagonal length = $\sqrt{{a^(2) }+ b^(2)}$
= $\sqrt{{2^(2) }+ 1.5^(2)}$
= 2.5 miles

To calculate how much shorter = ( 2 miles + 1.5 miles) - 2.5 miles
= 3.5 miles - 2.5 miles
= 1.0 miles

Hope this help !

Answer 2

Answer:

Answer:

idk

Step-by-step explanation:

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A store manager did a study to determine the amount of money the first 50 customers spent in her store. The data are approximately normally distributedwith a mean of $29.60 and a standard deviation of $10.50. The formula for normalizing data is: Z= (X−μ / σ) Z is the normal score X is a discrete data value μ is the mean σ is the standard deviation Determine the probability that a customer spent over $35. Enter your answer as a decimal to the hundredths place.

Answers

Simply input the data given, using the mentioned formula.
X=$35.00
μ=$29.60
σ=$10.50

Z= (X−μ / σ)
^^ This formula is actually wrong though... the correct way to write it is:

Z= (X−μ) / σ
Z=(35.00-29.60)/10.50
Z=5.4/10.50
Z=0.51

Nian's graden i 4 1 5 meters long 3 under 10 meter wide what is the area of nians garden

Answers

Answer:

14 meters squared

Step-by-step explanation:

The dimensions of this rectangle are 4 1/5 meters by 10/3 meters. The area of a rectangle is: $A=lw$ , where l is the length and w is the width.

Here, l = 4 1/5 and w = 10/3. We simply multiply them together:

A = (4 1/5) * (10/3)

Let's turn 4 1/5 into an improper fraction to make things easier: 4 1/5 = 21/5. Now:

A = (21/5) * (10/3) = 210/15 = 14

The area is 14 meters squared.

Hope this helps!

Answer:

14m²

Step-by-step explanation:

Area = length × width

length = 4⅕ = 21/5

width = 10/3

Area = 21/5 × 10/3

= 14m²

The coordinates of the vertices of ANGLE RST are R(-3,5), and S(4,5), and T(4,-2). Find the side lengths to the nearest hundredth and the angle measures to the nearest degree.

Answers

Side lengths: RS=7 and ST=7, and angle=90 degrees

Why?

Since second coordinates of R and S are the same so we can just count the length by adding first coordinate of R and first coordinate of S= |-3|+4=7

Since first coordinates of R is the same as first coordinate of T so we can just count the length by adding second coordinates of S and T=5+|-2|=7

Angle: RST is =90 degrees because triangle RST is right angled triangle. Why? Because RS is parallel to X axis(the same second coordinates of R and S) and ST is parallel to Y axis(the same coordinates of S and T) .

Round 2.6 to the nearest tenth

Answers

2.6 is already rounded to the nearest tenth.

If the original answer was 2.67345, it would be rounded to 2.7.
or
if it were 2.63421; it would be 2.6

The number after a decimal; (2.6 is the tenth)

816.45 = hundred
816.45 = ten
816.45 = one
816.45 = tenth
816.45 = hundredth

The first order was 13 bushes and 4 trees for a total of $487 the second order was 6 bushes and 2 trees for a total of $232 what were the costs of one bush and of one tree

Answers

Hagan asks a jowksbsbs lwks962

What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

Answers

The equation of circle is:
(x-a)^2+(y-b)^2=r^2 where C(a, b) is the center.
In order to find r you have to find the distance between C(-2, 1) and let's say A(-4, 1)

The formula for distance is:
$\sqrt{ ( y_(A)-y_{C )^(2) + (x_(A)- x_(C )^(2) )$
r = 2

The equation of circle is
(x+2)^2+(y-1)^2=4

I hope that this is the answer that you were looking for and it has helped you.

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