MATHEMATICS HIGH SCHOOL

If the smallest angle of a triangle is 20 degrees and it is included between sides of 4 and 7, then (to the nearest tenth) the smallest side of the triangle is 3.2 - true or false?

Answers

Answer 1

Answer:

Answer:

The answer is False

Step-by-step explanation:

we know that

Applying the law of cosines, find the length of the third side of the triangle

$c^(2)= a^(2)+b^(2)-2abcos(C)$

In this problem we have

$a=4\ units, b=7\ units, C=20\°$

substitute the values and solve for c

$c^(2)= 4^(2)+7^(2)-2*(4*7)*cos(20\°)$

$c= 3.5\ units$ -------> smallest side of the triangle

therefore

$3.5\neq 3.2$

Answer 2

Answer: Hello,
Al 'Kashi theorem says:

a²=4²+7²-2*4*7*cos 20°=12.37721...
==>a=3.518126381...≈3.5 ==>False.

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Write the equation of a line with a slope of 4 and a y-intercept of −3. 4x + y = −3 4x – y = −3 y = −3x + 4 y = 4x − 3

Answers

Knowing the slope and y-intercept of a line you can put its equation in slope-intercept form.
The slope-intercept form equation of a line is $y=mx+b$ where $m$ is the slope and $b$ is the y-intercept.
In this case, since the slope is 4 and the y-int. is -3, our equation must be
$\boxed{y=4x-3}$

y=4x-3

4 is the slope and -3 is the y intercept

By plugging these values into the slope intercept form: y=mx+b I came up with the previous answer-y=4x-3

m= the slope, and b=the y intercept

Write an equation of the line perpendicular to the given line that contains P.