A. float
B. sink
C. sink, then float
An object will float when:
A. buoyant force is equal to the weight of the object
B. buoyant force is less than the weight of the object
C. density is equal to the weight of the object
D. density is greater than the weight of the object
What is the buoyancy force on a 15 g object which displaces 60 mL of water? (Remember to change mL of water to grams and grams to kg)
A. 900 N
B. 25 N
C. 0.59 N
D. 0.25 N
An object has a density of 20 g/cm3. When placed in a cylinder, it displaces 5 mL of water. What is the mass of the object?
A. 0.25 g
B. 4.0 g
C. 100.0 g
Substance has a mass of 16.2 grams. It displaces 8.1 grams of water. What is its specific gravity?
A. 2.0
B. 5.5
D. 131.22
1) A. float
There are two forces acting on an object in the water: the weight of the object (downward) and the buoyancy (upward), which is equal to the weight of displaced water. If the weight of displaced water is greater than the weight of the object, it means that there is a net force directed upward, so the object will float.
2) A. buoyant force is equal to the weight of the object
As stated in the previous question, there are only these two forces acting on an object in the water (buoyant force and weight of the object), so if the two forces are equal, then the object is in equilibrium, so it will float.
3) C. 0.59 N
The buoyancy force is given by:
where
is the density of the liquid (water)
is the volume of displaced water
is the acceleration of gravity
Substituting numbers into the formula, we find
4) C. 100.0 g
The density of the object is 20 g/cm^3, which is greater than the density of the water (1 g/cm^3): this means that the object will sink, so its volume is equal to the volume of displaced water.
Therefore, we have:
- object's density:
- object's volume:
so, the mass of the object is
5) A. 2.0 g
The specific gravity of an object is given by the ratio between its density () and the density of a reference substance (), in this case water:
whe can rewrite each density as the ratio between mass and volume:
where the suffix o refers to the object, while the suffix w refers to the water. However, if we assume that the object is completely in the water, the two volumes are equal, so we can simplify the formula:
If the deflection of the spring is doubled, the force exerted by the spring will also be doubled.
The relationship between the deflection of a spring and the force it exerts is described by Hooke's Law, which states that the force exerted by a spring is directly proportional to its deflection. Mathematically, this can be expressed as:
F = kx
where F is the force exerted by the spring, x is the deflection of the spring, and k is the spring constant, which represents the stiffness of the spring.
If we double the deflection of the spring, then x becomes 2x, and the force exerted by the spring becomes:
F = k(2x) = 2kx
Thus, if the deflection of the spring is doubled, the force exerted by the spring will also be doubled (assuming the spring constant remains constant).
Learn more about the deflection here:
#SPJ6
Answer:
The force is doubled as well.
Explanation:
If you double the spring then the force doubles as well.
b. False
b. the distance between two wave troughs
c. the speed of energy of the wave
d. the lowest part of the wave
b. print currency
c. rule on conflicts
d. call Congress into session