Q14) When you break a bar magnet in half, how many poles does each piece have?

Answers

Answer 1

Answer: Each piece of magnet has only two poles, one north and one south. So if you break a bar magnet into two halves, the piece initially consisting the north pole at the edge automatically creates the south pole at the break point and the part consisting south pole creates North pole at the edge. So each piece has 2 poles.

Answer 2

Answer:

A magnet is an item or substance that generates a magnetic field. The broken pieces of the magnet will have 4 poles.

What are magnets?

A magnet is an item or substance that generates a magnetic field. This magnetic field is invisible, but it is responsible for a magnet's most remarkable property: a force that attracts or repels other ferromagnetic elements such as iron, steel, nickel, cobalt, and others.

When a magnet is broken into two pieces, it produces two complete magnets, each with its own north and south poles and the same orientation as the original.

For example, if you break a 12-inch bar magnet with N on the left end and S on the right end midway between the two ends, you'll get two magnets with N on the left end and S on the right end, as seen in the illustration below.

Hence, the broken pieces of the magnet will have 4 poles.

Learn more about Magnets:

brainly.com/question/19542022

Related Questions

A bowling ball with a mass of 7.10 kg has a velocity of 5 m/s. what is the bowling ball's momentum?
Inertia is ______ to mass. directly proportional inversely proportional equal to not related to
suppose that a particle at rest with mass m decays into a photon and another particle with mass m/2 , which recoilds in a direction opposite to the photon. Using the conservation of energy and momentum find the momentum of the recoiling particle
The inventor of the photographic process in which a photograph produced without a negative by exposing objects to light on light sensitive paper, is named _____________a. Man Ray c. Dorothea Lange b. Richard Avedon d. Pablo Picasso
Calculate the resistance of a lamp that draw 0.75 A current when connected to 4.5 V.

What causes the earths crust to move ?

Answers

Upwelling currents in the molten material beneath the crust.

The rocks that make up the crust are light, compared with the metal-rich material beneath. The crust floats on top like an iceberg. Slow-moving currents underneath propel the continents around the surface

The movement of magma underneath earth's crust.

Why Newton's law of gravitation also called universal law?

Answers

Answer:

Explanation:

Newton's law of gravitation states that every particle of matter attracts any other particle in the universe with a force directly proportional to the product of there masses and inversely proportional to the square of the distance between them.

This law is also called universal law because it is applicable to all masses at all distances irrespective of the medium.

a bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

Answers

The expression for the bullet's speed vbullet is $v=\sqrt{(2\mu_k (m+M)gd)/(m)}$ and the speed of a 9.0 g bullet is v=16.8 m/s

Explanation:

A bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

The initial kinetic energy of the bullet is given by

$K_i = (1)/(2)mv^2$

where

m is the mass of the bullet

v is the initial speed of the bullet

The expression for the bullet's speed vbullet is

$F=\mu_k (m+M) g$

where

$\mu_k$ is the coefficient of kinetic friction

g is the acceleration of gravity

The work done by the force of friction is

$W=-Fd = -\mu_k (m+M)g d$

where d is the displacement of the block+bullet.

Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:

$W=K_f - K_i = -K_i$

And so

$-\mu_k (m+M) g d = -(1)/(2)mv^2$

By solving for v, the solution for the bullet speed:

$-\mu_k (m+M) g d = -(1)/(2)mv^2\nv=\sqrt{(2\mu_k (m+M)gd)/(m)}$

The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.

We have:

the mass of the bullet, m = 9.0 g = 0.009 kg

the mass of the block, M = 12 kg

the distance covered by the block+bullet, d = 5.4 cm = 0.054 m

the coefficient of friction, $\mu_k = 0.20$

the acceleration of gravity, $g = 9.8 m/s^2$

By substituting, we got

$v=\sqrt{(2 (0.20) (0.009 kg+12 kg)(9.8 m/s^2)(0.054 m))/(0.009 kg)}=16.8 m/s$

Learn more about friction brainly.com/question/5884009

#LearnWithBrainly

uk=2m*the normal force
the distance d is needed only if you were asked about work

Kate is working on a project in her tech education class. She plans to assemble a fan Motor. Which form of energy does the motor convert most of its electric energy into

Answers

Answer: Motor convert most of its electric energy into mechanical energy.

Explanation:

An electric motor is an electric machine which converts electric energy into mechanical energy.

Electrical energy → Mechanical energy.

The principle on which it works is that when current carrying conductor is placed under the influence of magnetic field it experiences force which termed as mechanical force.

kinetic energy. the electricity makes the fan move. it uses potential energy and converts it into kinetic energy from the electricity.

Which statement is correct? a) 1 in. = 2.54 cm b) 7 in. = 17.68 cm c) 1 ft = 12 in. d) 74 in. = 1 yd

Answers

Answer:

a) 1 in. = 2.54 cm

Explanation:

Final answer:

The correct statement is a) 1 in. = 2.54 cm. To convert inches to centimeters, multiply the number of inches by the conversion factor 2.54 cm/1 in.

Explanation:

The correct statement is a) 1 in. = 2.54 cm.

To convert inches to centimeters, you can multiply the number of inches by the conversion factor 2.54 cm/1 in. For example, if you want to convert 7 inches to centimeters, you would multiply 7 in. by 2.54 cm/1 in. This gives you 17.78 cm, which is approximately equal to 17.68 cm (as stated in option b).

Option c) 1 ft = 12 in. and option d) 74 in. = 1 yd are also correct statements, but they are not directly related to the conversion between inches and centimeters.

Learn more about Conversion between inches and centimeters here:

brainly.com/question/29750822

#SPJ11

What is the velocity of a 500-kilogram elevator that has 4,000 joules of energy?

Answers

The velocity of a 500-kilogram elevator that has 4,000 joules of energy is 4m/s.

KINETIC ENERGY:

The kinetic energy of a substance is its energy during motion. It can be calculated using the formula below:

K.E = ½m.v²

Where;

m = mass of the elevator (kg)

v = velocity of the elevator (m/s)

According to this question, the energy of the 500kg elevator is given as 4,000 joules, hence, the velocity can be calculated as follows:

V = √K.E × 2/m

V = √4000 × 2/500

V = √8000/500

V = √16

V = 4m/s

Therefore, the velocity of a 500-kilogram elevator that has 4,000 joules of energy is 4m/s.

Learn more: brainly.com/question/10703928?referrer=searchResults

The Energy is Kinetic Energy.

Kinetic Energy = 1/2*mv², Where m is mass in kg, v is velocity in m/s

Energy is 4000 Joules, v = ?
mass, m = 500kg

1/2*mv² = E

1/2*500*v² = 4000

v² = (2*4000) / (500) Using a calculator

v² = 16 Taking square root

v = √16

v = 4

Velocity of object is 4 m/s.

Other Questions

What word is used to describe knowledge about the universe and the method of obtaining that knowledge?

What is a newton equal to in terms of units of mass and acceleration?

What’s the kinetic energy of the object? Use .Erica is competing in the shot put event at a track meet. She hurls a shot with a mass of 4 kilograms at a speed of 9 meters/second. The shot’s kinetic energy is joules.

In a series circuit, if one of the bulbs blew out, the other bulb woulda. not be able to light up. b. stay lit but be very dim. c. stay lit in the same way. d. stay lit and be twice as bright as when both bulbs were lit.