The greatest common factor of 45 and 72 is 9.
The given numbers are
45 and 72
We know that,
The greatest common factor (GCF) is the biggest number that is a factor of two or more numbers.
The greatest number (factor) divides them, yielding a Natural number. Once all of the number's variables have been identified, there are a handful that are shared by both.
The greatest common factor is the largest number found among the common factors. The GCF is often referred to as the HCF (Highest Common Factor).
Now factorize 45
45 = 3x3x5
Now factorize 72
72 = 2x2x2x3x3
Now the common factors are:
3x3
= 9
Thus the GCF ⇒ 9
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Answer: The area of the path is 280 ft^2
(Note that 280 ft^2 means “280 feet squared”)
Step-by-step explanation: The first clue in this question is the dimensions of the rectangular garden which have been given as 29 ft by 37 ft. So we can conveniently compute the area of the garden as follows;
Area = L x W
(Length is 37 ft and Width is 29 ft)
Area = 37 x 29
Area = 1037 ft^2
However there is a path surrounding the garden which is 2 ft wide on all four sides. This means both borders of the length have an extra 4 feet of measurement while both borders of the width also have an extra 4 feet of measurement. So, if the surrounding border and garden is measured altogether, the length would become (37 + 4= 41) 41 feet while the width would become (29 + 4 = 33) 33 feet. So the area of the garden and the surrounding path inclusive can be calculated as
Area = L x W
Area = 41 x 33
Area = 1353 ft^2
To determine the area of ONLY THE SURROUNDING PATH, we simply deduct the area of the GARDEN ONLY (1073 ft^2) from the area of GARDEN AND SURROUNDING PATH (1353 ft^2)
Therefore area of the path surrounding the garden becomes
Area of path = 1353 - 1073
Area of path = 280 ft^2
seconds. What is its unit rate of speed?
Answer:
The speed at which the satellite travel is 6.80 miles per second
Step-by-step explanation:
Given as :
The distance cover by satellites = 29 miles
Or, The distance cover by satellites = miles
The Time taken by satellite to travel with this speed = 4 sec
Or, The Time taken by satellite to travel with this speed = seconds
Let the Speed with which the satellite travel = s miles per second
Now, As we know
Speed =
Or, s =
or, s =
∴ s = 6.80 mps
So, speed = s = 6.80 miles per second
Hence The speed at which the satellite travel is 6.80 miles per second Anwser