Michelle has 5coins worth 75 cents what coins did she have?

Answers

Answer 1
Answer: we need to divide the total cents by the amount of coins so that we know how much each coin is worth:
75/5 = 15
but there aren't coins worth 15 cents.
So lets accomodate the total in known coins:
1 cent, 5 cents, 10 cents, 25 cents, 50 cents.
take this combination:
2(25) + 2(10) + 1(5) = 50 + 20 + 5 = 75
so she could have 2 coins of 25 cents, and 2 coins of 10 cents, and 1 coin of 5 cents
Answer 2
Answer: One possibilities there is that there is:
2 quarters
2 dimes
1 nickel

25 + 25 + 10 + 10 + 5 = 75

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PLEASE HELP I GIVE THANKS

Answers

4x+(3x-8)=90

4x+3x-8=90

7x=98

x=98/7

x=14

If x=14,

angle CDJ is:

(3(14)-8) degrees

=34 degrees
4x 3x -8
angle ADJ is a right angle, so it is equal to 90 degrees. so if you added the two missing numbers together (4x and 3x-8) it would have to equal 90.
4x+3x-8=90
7x-8=90
7x=98
x=14.
plug x back into the equations to find your angles.
3(14)-8 and 4(14)

The terms are 4/10, n/30. The net price is $919.60. What is the cash price using the complement method? '

Answers

Answer:

Cash price using complement method id $882.8

Step-by-step explanation:

When a vendor includes terms of 4/10, n/30 , the '4' represents 4% of the amount owed , the '10' represents 10 days, the 'n' represents net and the '30' represents 30 days.

So the terms 4/10, n/30 indicate that the buyer may take an early discount of 4% of the amount owed is remitted in 10 days instead of normal 30 days.

In other words, buyer can choose any one of the following:

1) Pay within 10 days and deduct 4% of the net amount owed.

2)Pay in 30 days and take no discount.

For finding cash price using complement method, we have to find the complement of discount percentage= 100-discount percentage=100-4=96

So cash price using complement method = net price X complement of discount percentage in decimals

                                                                     = 919.6 X 0.96

                                                                     = $882.8

Solve 3x+2y=5 and x+y=3 as a graph, substitution, or elimination?

Answers

Step-by-step explanation:

multiply second equation by -2

-2 × (x+y) = 3➡ -2x - 2y = -6 now add up both equations

3x + 2y - 2x-2y = 5-6 ➡x = -1 (-2y eliminated +2y)

now use the value we found for x in the second equation to find the value of y

x + y = 3 we found x as -1

-1 +y = 3 ➡y = 4

What's.5 equal to in percentage

Answers

0.5 is 50%
0.12 is 12%
0.155 is 15.5%
.5 is equal to .50 in percentage because percentage and decimals are the same.

Can you please help me with the sheet??

Answers

1. 25 minutes
2. 41 minutes
3. 21 wheels
4. 7
5. 160
6. 415 miles

a scale drawing of a rectangular park is 5 inches wide and 7 inches long. the actual park is 280 yards long. whats the area of the actual park, in square yards?

Answers

The actual area of the park in square yards from the given scale is;

Actual area of park = 56000 yds²

We are told that;

There is a scale drawing of a rectangular park with dimensions;

Width = 5 inches

Length = 7 inches

Now, we are told that the Actual length of the park is 280 yards.

Since the length on the scale drawing is 7 inches, then it means that;

7 inches represents 280 yards

Thus, 1 inch will represent; 280/7 = 40 yards

Thus, actual width = 5 × 40

Actual width = 200 yards

Formula for area of rectangle is;

Area of rectangle = Length × width

Thus;

Actual area of rectangle = actual length × actual width

Actual area of rectangle = 280 × 200

Actual area of rectangle = 56000 yds²

Read more at; brainly.com/question/13654487

Answer:

Area of the actual park is 56000 square yards.

Step-by-step explanation:

A scale drawing of a rectangular park has dimensions as 5 inches width and 7 inches length.

Actual length of the park has been given as 280 yards.

So scale factor used in the drawing is 7 inches = 280 yards

Or 1 inch = 40 yards

Since width of the rectangular park is = 5 inch  

So actual width of the park will be = 5×40 = 200 yards

Now we can calculate the area of the park.

Actual area of the park = Length × Width

= 280×200

= 56000 yards²

Therefore, area of the actual park is 56000 square yards.