Answer:
See below
Step-by-step explanation:
Lets label the consecutive odd numbers as 2n+1 and 2n+3 where n is an integer.
We need to prove that
((2n + 3)^2 - (2n + 1)^2 is a multiple of 8.
Using the difference of 2 squares on the left side:-
(2n + 3 + 2n + 1)(2n + 3 - (2n + 1)
= (4n + 4)(2)
= 8n + 8 which is a multiple of 8
The difference between squares of consecutive odd numbers can be expressed as 4n+4 which is a multiple of 8.
Let's take two consecutive odd numbers. We can express an odd number as 2n+1 where n is any integer. So, the consecutive odd number will be 2n+3 (adding 2 to the previous one).
Now, the squares of these consecutive numbers are (2n+1)² and (2n+3)² respectively.
The difference between these squares is (2n+3)² - (2n+1)². Applying the formula a² - b² = (a+b)(a-b), we get 4n+4 as the answer which is a multiple of 8 as 8 divides it without a remainder.
So the difference between the squares of consecutive odd numbers is a multiple of 8.
#SPJ3
Answer:
An equivalent expression is 18(2 + x)
Step-by-step explanation:
To find this, look for the greatest common factor. Since both terms are divisible by 18 equally, we take 18 out of each term. Then we divide both terms by 18 and express in a parenthesis.
18(2 + x)
The answer is there
Answer:
-6w-22
Step-by-step explanation:
-3(2w+6)-4=
= -6w-18-4=
= -6w-22
So,choose C (none of the above) :)
heartbeats in minutes
Answer:
a = 3 and b = 4
Step-by-step explanation:
Independent Equations
Lines intersect
One solution
In this case the two equations describe lines that intersect at one particular point. Clearly this point is on both lines, and therefore its coordinates (x, y) will satisfy the equation of either line. Thus the pair (x, y) is the one and only solution to the system of equations. One solution is called "consistent". This shows two distinct non-parallel lines that cross at exactly one point. This is called an "independent" system of equations, and the solution is always some x, y-point.