11. What's the lateral area of a right cylinder if the radius of the base is 12mm and the altitude of the cylinder is 5 times the base radius? Round your answer to the nearest whole number.

Answers

Answer 1

Answer: radius of base: 12mm
height: 60mm

A=2 $\pi$ rh
A=2 $\pi$ (12)(60)
A=2(720) $\pi$
A=1440 $\pi$
A= approximately 4523.89

The lateral area of a right cylinder if the base is 12mm and the altitude is 5 times the base's radius is 4524mm^2

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Multiply and simplify the product.–12i × 3i
Select the product.

a.36

b. -36

c. 36i

d. -36i

Answers

The multiplication and simplification of the polynomial –12i × 3i gives 36

What is a complex number?

A complex number is a number of the form a + bi, where a and b are real numbers, and i = √-1

i² = (√-1)² = -1

Given the complex number:

–12i × 3i

multiplying and simplifying gives:

= -36 * i² = -36 * -1 = 36

The multiplication and simplification of the polynomial –12i × 3i gives 36

Find out more on complex number at: brainly.com/question/10662770

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Hello,
(-12i)*(3i)=-36i²=36
Answer A

Chang 0.83 into a fraction

Answers

answer: 83/100

there you go!!!!

Hope it helps

Create a “fraction” with 0.83 in the numerator and 1.0 in the denominator:

0.83/1.0

Move the decimal point in 0.83 two places to the right to turn it into a whole number; move the decimal point in the denominator the same number of places. Do this one decimal place at a time:

0.83/1.0=8.3/10.0=83/100

At this point, you can drop the decimal points and trailing zeros in both the numerator and denominator.

What is the answer to this problem... f(x)3x+7=

Answers

There really isn't a answer. Let me explain, this is a function. A function shows what operation you have to do to get a y value or any kind of value. Whenever it has a f(x) or any variable in the 'x' part you will automatically know that it's a function. So what you do is substitute any number for the variable that's there, any number, whether it's 100 or 1. So in this case a x is what we have to put in a substitute for. So let's try 1. 1x3 = 3, 3+7 is 10. So the function of x for 1 is 10. Now keep doing that and you'll get numbers which will turn into points in a graph (when we substituted in a 1 and got a result that's the y value) and that's the "answer".

Help answer all questions please and tell me how you got the answers

Answers

8. You start with 240 gallons if in march you use 40% (.4(240)=96) you used 96 gallons in march, leaving you with 144 gallons. If you then used 25% in April (.25(144)=36) you would have used 36 gallons leaving you with 108 gallons at the end of April.

9. If 2277 is 110% the number of 2013 to find what 2013 was you would divide by 110%(1.1)
2277/1,1=2070 at the end of 2013
If 2070 is 90% then we will want to divide by 90% (.9) to get the year before that
2070/.9=2300 so 2300 people were signed up in the year 2012

10. 57.5=p(250)
to solve this divide both sides by 250 to get p=.23
As for the different elements to the equation, there are various answers such as what percentage of people donated $250 if the average amount of money donate from each one is 57.5 although that may no be what you instructor is looking for. pretty much just make up something that sounds okay and you should be fine

Every month Neha takes a fixed amount of ₹3750 from her mother for her expenses. What is the amount she is spending in a year. What is the quality reflected here?

Answers

Answer:

Yearly expenses = ₹45,000

Step-by-step explanation:

Given:

Monthly expenses = ₹3,750

Find:

Yearly expenses

Computation:

Yearly expenses = 12 x ₹3,750

Yearly expenses = ₹45,000

Neha is unemployed and his expenses are totally fixed during the whole year.

a rectangular field with a area of 8000m2 is enclosed by 400m of fencing. determine dimensions to nearest tenth of a metre

Answers

$field:x\ *\ y\n\n \left\{\begin{array}{ccc}x\cdot y=8000\n2x+2y=400&/:2\end{array}\right\n\left\{\begin{array}{ccc}x\cdot y=8000\nx+y=200&\to x=200-y\end{array}\right\n\nsubstitute\ to\ x\cdot y=8000\n\n(200-y)\cdot y=8000\n\n-y^2+200y-8000=0\n\n\Delta=b^2-4ac;\ \Delta=200^2-4\cdot(-1)\cdot(-8000)=40000-32000=8000\n\ny_1=(-b-\sqrt\Delta)/(2a);\ y_2=(-b+\sqrt\Delta)/(2a)$

$\sqrt\Delta=√(8000)=√(1600\cdot5)=40\sqrt5\n\ny_1=(-200-40\sqrt5)/(2\cdot(-1))=(-200-40\sqrt5)/(-2)=100+20\sqrt5\approx144.7\ (m)\n\ny_2=(-200+40\sqrt5)/(2\cdot(-1))=(-200+40\sqrt5)/(-2)=100-20\sqrt5\approx55.3\ (m)\n\nx_1\approx200-144.7=55.3\ (m)\n\nx_2\approx200-55.3=144.7\ (m)\n\nAnswer:Dimension of the field is:55.3m\ *\ 144.7m$

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