Answer:
Objects in free-fall do not experience air resistance.
Explanation:
This comes from the definition of free-fall: an object in free fall is an object which is falling and the only force acting on it is gravity. Therefore, air resistance is not present for an object in free-fall. As a result, the acceleration of any object in free-fall is always equal to g (gravitational acceleration), and so all the objects fall with the same velocity and same time, regardless of their mass.
If the object is massive then the acceleration of gravity is faster, such objects will free fall more quickly than lighter objects. The objects in free fall do not experience air resistance are all true statements because the force of gravity which depends upon weight.
It is directly proportional to the weight. Yet the mass and weight are not same because mass is only value in kilograms but the weight is the value in which mass and gravitational acceleration are included. However, its unit is kilograms - 2 which is equal to Newton law of formula which is also unit of force.
Jeremy wants to buy some snacks. He walks four blocks east and two blocks south to get to the closest convience store to his house. How far away is store from his house, directly?
2)A slanted vector has a magnitude of 41 N and is at an angle of 23 degrees north of east. What are the magnitude and direction of the horizontal and vertical components of this vector?
3)A horizontal component vector has a magnitude of 11 m. If the resultant vector forms and angle with this component of 19 degrees, what is the magnitude of the resultant vector?
1) The distance of the store from the house is 4.47 blocks
2) The horizontal component of the vector is 37.7 N, the vertical component is 16.0 N
3) The magnitude of the resultant vector is 11.6 m
Explanation:
1)
Jeremy's motion is divided into two parts:
- First, a motion of 4 blocks east
- Then, a motion of 2 blocks south
Here we want to measure the distance between the initial and final position of Jeremy.
We notice that the two displacements are perpendicular to each other, so they correspond to the sides of a right triangle, of which the hypothenuse is the distance between the initial and final point. Therefore, the distance can be found by using Pythagorean's theorem:
So, 4.47 blocks.
2)
The horizontal and vertical components of the vector can be calculated as
where
v = 41 N is the magnitude of the vector
is the angle between the direction of the vector and the x-axis (which corresponds to the east direction)
Substituting numbers into the equations, we find
3)
In the previous part, we said that the horizontal component of a vector is given by
where
v is the magnitude of the vector
is the angle
In this problem we know that:
is the horizontal component
is the angle
Therefore, we can re-arrange the equation to find v, the magnitude of the resultant vector:
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Answer:
9.23 m/s
Explanation:
Let, the initial velocity be ux.
The horizontal velocity remans the same. So, time required, t = 25/ux
For vertical component, we know,
h = uy*t + (1/2)*g*t^2 [ g is positive because ball is falling downward ]
Putting in the values, we get,
36 = 0*(25/ux) + 1/2 * 9.81 * (25/u)^2
36 = 3065.625/u^2
u^2 = 85.15625
u = 9.23
[ If there's a problem with the solution, please inform me ]
As per the modern classificationsystem, the class, order, genus, species is arranged from least specific to most specific one. The correct option is C.
The term classification can refer to one or more of the following: the process of classifying the resulting set of classes the classification of elements into predefined classes Classifying, in its broadestsense, is a fundamental concept and a component of almost all activities.
In 1956, Herbert FaulknerCopeland (1902-1968) proposed the four kingdom classification.
Monera, Protista, Plantae, and Animalia were the four kingdoms. He classified unicellular organisms into two groups: the Monera kingdom and the Protista kingdom.
The classificationsystem provides a wealth of information about organism characteristics. Using scientific names as a shorthand method of describing a plant or animal can thus be beneficial.
Thus, the correct option is C.
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Your question seems incomplete, the missing options are:
A) species, genus, family, order
B) phylum, class, genus, order
C) class, order, genus, species
D) phylum, order, species, family
From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.
We need to find its height.
We will use the formula P.E = mgh
Therefore h = P.E / mg
where P.E is the potential energy,
m is mass in kg,
g is acceleration due to gravity (9.8 m/s²)
h is the height of the object's displacement in meters.
h = P.E. / mg
h = 14000 / 40 × 9.8
h = 14000 / 392
h = 35.7
Therefore the canon ball was 35.7 meters high.
The height of the cannon ball to have 14000 J of potential energy is approximately 357.14 meters. This is calculated using the formula for potential energy: PE = mgh, and solving for 'h'.
The potential energy (PE) of an object is given by the formula PE = mgh, where 'm' is the mass of the object, 'g' is the acceleration due to gravity (standard approximate value is 9.8 m/s² on Earth), and 'h' is the height. In your question, we want to find the height 'h'. Given that the potential energy is 14000 J and the mass of the cannon ball is 40 kg, we can rearrange the formula to solve for 'h': h = PE / (m*g).
So, inputting the given values, h = 14000 J / (40 kg * 9.8 m/s²). Solving this, we find that the height is approximately 357.14 meters. This means the cannon ball was at around this height to have 14000 J of potential energy.
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