(2,?) is on the line 4x – 5y = -7. Find the other half of the coordinate.

Answers

Answer 1

Answer: this is the work I did

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How many zeros would you find at the end of 100!, fi you ex- pandeditoutinbaseten?

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Answer:

Hope this helps! :)

You would find 24.

Four hundred grams of grass seed are used for every 100 m2. Find the amount of seed needed, in kilograms, to cover 3000 m2?

Answers

400 / x = 100 / 3000 <=>
400 / x = 1 / 30 <=.>
x = 400 * 30 <=>
x = 12000 kilograms of grass.

How would i solve 4x-3y=8
5x-2y=-11

using the elimination method?
i'm in algebra 1 and we had a sub the day we were doing this and he was terrible explaining the situations on the worksheet. please explain

Answers

To use the elimination method, the coefficient of one variable in one equation must be the opposite number of the coefficient of the same variable in the second equation.

$4x-3y=8 \n5x-2y=-11$

Here you can multiply the first equation by 2, and the second equation by -3.

$4x-3y=8 \ \ |\cdot 2 \n5x-2y=-11 \ \ |\cdot (-3) \n \n8x-6y=16 \n-15x+6y=33$

Now you just add the equations by sides and solve for one variable.

$8x-6y=16 \n \underline{-15x+6y=33 } \n8x-6y-15x+6y=16+33 \n8x-15x=16+33 \n-7x=49 \nx=-7$

Now you solve for the other variable by substituting -7 for x in one of the equations.

$4x-3y=8 \n4 \cdot (-7)-3y=8 \n-28-3y=8 \n-3y=8+28 \n-3y=36 \ny=-12$

You could choose x at the beginning as well. Then you'd have:
$4x-3y=8 \ \ |\cdot (-5)\n5x-2y=-11 \ \ |\cdot 4 \n \n-20x+15y=-40 \n\underline{20x-8y=-44 \ \ \ \ \ \ } \n-20x+15y+20x-8y=-40-44 \n15y-8y=-40-44 \n7y=-84 \ny=-12 \n \n4x-3y=8 \n4x-3 \cdot (-12)=8 \n4x+36=8 \n4x=8-36 \n4x=-28 \nx=-7$

So the answer is:
$x=-7 \n y=-12$

Answer:

x=-7 and y=-12

Step-by-step explanation:

The jars of paint in the art room have different amounts of paint. The green paint jar is 4/8 full. The purple paint jar is 4/6 full. Which paint jar is less full?

Answers

4/8 is less full because if we find the least common denominatior than 4/8 will be 12/24 and 4/6 will be 16/24 so the one with 12/24 is less which is 4/8

The area of a rectangular wall of a barn is 108 square feet. Its length is 12 feet longer than the width. Find the length and width of the wall of the barn.

Answers

Area = Width x Length
Area = 108
Square root of 108 = 10.4

108/ 9 = 12 ...12 is not 12 larger than 9
108/ 6 = 18 ...18 is 12 larger than 6

108 = 6 x 18

Width = 6
Length = 18

Final answer:

To find the length and width of the wall of the barn, set up an equation using the given information. Solve the equation by factoring, and find the values of x and x + 12, which will be the width and length of the wall, respectively. The width of the wall is 6 feet, and the length is 18 feet.

Explanation:

To find the length and width of the wall of the barn, we can use algebra. Let's say the width of the wall is x. According to the problem, the length is 12 feet longer than the width, so the length is x + 12.

The area of a rectangle is found by multiplying the length by the width, so we can set up the equation

x(x + 12) = 108.

Solving this equation will give us the values of x and x + 12, which will be the width and length of the wall, respectively.

The equation is x(x + 12) = 108.

Expanding the equation gives x^2 + 12x = 108.

Rearranging the equation to bring everything to one side gives

x^2 + 12x - 108 = 0.

Factoring the quadratic equation gives (x + 18)(x - 6) = 0.

Setting each factor equal to zero gives x = -18 or x = 6.

Since we can't have a negative width, the width of the wall is 6 feet.

Therefore, the length of the wall is x + 12 = 6 + 12 = 18 feet.

Learn more about Solving equations to find length and width of a rectangular wall here:

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Use the relation S { (3,4) , (2,3), (1,2), (2,1)} for questions 1 and 21. State the domain and range of S
2. Is S a function? Explain your reasoning.

Answers

Answer:

HOPE THIS HELPS!!

Step-by-step explanation:

1. The domain and range of relation S are as follows:

Domain: The domain refers to the set of all input values in a relation. In this case, the domain of S is {3, 2, 1}, which corresponds to the first element of each ordered pair in the relation.

Range: The range refers to the set of all output values in a relation. In this case, the range of S is {4, 3, 2, 1}, which corresponds to the second element of each ordered pair in the relation.

2. No, relation S is not a function.

To be considered a function, each input value (or element in the domain) should have only one corresponding output value (or element in the range). However, in the given relation S, the input value 2 is associated with both the output values 3 and 1.

Since one input value is associated with multiple output values, S fails the definition of a function.

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