4:3 and 25:45 are equal ratios. True or false ?

Answers

Answer 1
Answer: False. When simplified, 25:45 is equal to 5:9. Therefore, the two ratios are not equal

Related Questions

What is the correct label for the angle?
If K is the midpoint of HJ, HK equals x+6, and HJ equals 5x-6, then KJ equals?
The value of Maggie's car decreased by 20% since last year, when she bought it. If the car is now worth $15,000.00, how much was the car worth when she bought it? A. $20,000.00 B. $17,647.06 C. $18,000.00 D. $18,750.00
Help me find the degree of this polynomial
I can't figure this outthis question was on my exam and I got it completely wrong (I have a graphing calculator capble of matrices so yo don't have to solve the system of equations by hand, use rref (reduced row echelon form))values of a, b, and c and the equation of the graph of the parabola y=ax^2+bx+csuch that is passes through the points (2,-15) (-5,-29) (-3,5) rewrite it in the form (x-h)^2=4P(y-k) show all workif I were to sub the points in I would ge(2,-15): -15=4a+2b+c (-5,-29): -29=25a-5b+c (-3,5): 5=9a-3b+cthen solve for a, b and c I don't know how to solve, please help(if I don't undestand your answer, I will either report or ask you to explain more)

Ryker is given the graph of the function y= 1/2x^2 - 4 . He wants to find the zeros of the function but is unable to read them exactly from the graph. Find the zeros in simplest radical form

Answers

y= (1)/(2)x^2 - 4 \n \ny=0 \n \n (1)/(2)x^2 - 4 =0\ \ / *2\n \nx^2-8 =0 \n \n(x-√(8))(x+√(8))=0 \n \n x-√(4 \cdot 2)=0 \ \ or \ \ x+√(4 \cdot 2)=0 \n \n x-2√( 2)=0 \ \ or \ \ x+2√( 2)=0 \n \n x=2√( 2) \ \ or \ \ x=-2√( 2)

HELP MEEEEE PLSSS guysssss

Answers

Answer:

E, 3.

Step-by-step explanation:

Since both f(x) and g[f(x)] are quadratic polynomials, g(x) must also be a linear polynomial.

Let g(x) = Ax + B, where A and B are constants to be determined.

Then we have A[2x² - 3x + 1] + B ≡ x² - (3/2)x + 3.

=> A = 1/2 and B = 5/2.

Hence, f[g(-1)] = f[(1/2)(-1) + (5/2)] = f(2) = 2(2)² - 3(2) + 1 = 3. (E)

CWhich dimensions can create more than one triangle?
three angles measuring 75°, 45°, and 60°
three sides measuring 7 m, 10 m, and lym
three angles measuring 40°, 50%, and 60°
three sides measuring 3 cm, 4 cm, and 5 cm

Answers

Answer:

Step-by-step explanation:

three angles measuring 75°, 45°, and 60°

75+45+60 = 180 -> can create triangle

three sides measuring 7 m, 10 m, and lym (assume this is 16)

satisfy this a-b<c<a+b -> can create triangle

three angles measuring 40°, 50%, and 60°

40+50+60 = 150 ≠ 180 -> cannot create triangle

three sides measuring 3 cm, 4 cm, and 5 cm

satisfy this a-b<c<a+b -> can create triangle

Given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line.

Answers

Here, 2x - 3y - 5 = 0

3y = 2x - 5

Divide the equation by 3, 
y = 2/3x - 5/3

Compare it with,y = mx + c
So, slope (m) = 2/3

In short,Your Answer would be: 2/3

Hope this helps!

Answer:

2/3

Step-by-step explanation:

Please help! Math Homework! Slope Intercept form

Answers

Answer:

y=-2/6x-4

Step-by-step explanation:

Answer:

Y=-3x+4

Step-by-step explanation:

while still in the hospital, the doctor writes an order for an antibiotic at 400mg / kg / day. You are nervous now because the nurse was wrong before. Assuming that you weigh 132 lb, determine how many milligrams should you be given. What is the equivalent number of grams? ( Hint: 1000mg = 1 g and mg / kg / day = mg/ kg × day)

Answers

Answer:

Patient will require 23950 mg or 23.95 gm of the antibiotic per day.

Step-by-step explanation:

The doctor has written an antibiotic at 400 mg per Kg body weight per day (400 mg/Kg/day).

Weight of patient is 132 lb.

So we will convert it into kilograms.

Since 1 lb = 0.4536 Kg

Therefore, 132 lb = 132 × 0.4536

                            = 59.875 kg

Weight of the patient is 59.875 kg

Now we can calculate the dose of the antibiotic by this weight of the patient.

∵ 1 Kg patient requires dose of antibiotic = 400 mg

∴ 59.875 Kg patient will require the dose = 400 × 59.875

                                                                     = 23950 mg

We know 1 mg = (1)/(1000) gms

So 23950 mg = (23950)/(1000) gms

                       = 23.95 gm per day

Therefore, patient will require 23950 mg or 23.95 gm of the antibiotic per day.

123 lb * (0.4536 kg/lb) * 300mg/(kg · day) = (123 * 0.4536 * 300) mg/day = 16737.84 mg/day 16737.84 mg/day * 1g/(1000mg) = 16.73784 g/day