The value of Maggie's car decreased by 20% since last year, when she bought it. If the car is now worth $15,000.00, how much was the car worth when she bought it? A. $20,000.00

B. $17,647.06

C. $18,000.00

D. $18,750.00

Answers

Answer 1

Answer: 15,000 x A 15,000 = .8A
.80 1.0

15,000 = A
.80

A = 18,750 the answer is D

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Johnathon can jog 3 2/5 miles in 7/8 hour. Find his average speed in miles per hour
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What percent of 61 is 152.5?
Please solve equations by completing square
Which equation represents a line that is parallel to the line whose equation is y = -3x - 7?y = 3x + 4 y = -3x + 7 y = (1/3x) + 1 y = (-1/3x) + 2

What is the value of sin67.5? use half angle formula

Answers

The solution wouldbe like this for this specific problem:

sin(67.5) = sin(135/2)
sin(x/2) = +/- √((1 - cos(x))/√2
sin(67.5) = √(1 - cos(135))/√2 = √(1 + √2/2)/√2 = √(√2/4 + 1/2) = 0.9239

I am hoping thatthis answer has satisfied your query and it will be able to help you in yourendeavor, and if you would like, feel free to ask another question.

At Southwest HS, the number of student in band is 1 3/4 times the number in orchestra. If 56 students are in orchestra, how many are in band?

Answers

It is important to take note of all the information's that are given in the question. It would be easy to solve the problem based on the information's given in the question.
Number of students in orchestra = 56
The number of students in band is = 1 3/4 times that are in orchestra
Then
Total number of students in band = (7/4) * 56
= 7 * 14
= 98
So 98 students are there playing in the band. I hope the answer and the procedure is clear to you. In future you can use this procedure to solve similar kind of problems without requiring any help from outside.

56 students* (1 3/4)= 98 students.

There are 98 students in the band~

What are the domain and the range of the function pictured in the graph?

Answers

Answer:.The domain and range of a function are the sets of possible input and output values-My answer :D

Step-by-step explanation:

.The domain and range of a function are the sets of possible input and output values-My answer :D

I’ll try to help you with that. The domain of a function is the set of all possible input values for the function, while the range is the set of all possible output values. Unfortunately, I don’t have access to the graph you’re referring to. However, I can provide you with some general information on how to find the domain and range of a function.

To find the domain of a function, you need to determine all possible values of x that can be used as input to the function, which will result in a real number as the output 12. The range of a function is the set of all possible output values of a function 34.

I hope this helps <3

translate the word phrase into a variable expression. The product of a number and 5 is decreased by 2.

Answers

It would be:
5n - 2

Hope that helps :D

Can someone help 400 divide 700

Answers

Answer:

0.57142857142

Step-by-step explanation:

Use a calculator.

A 40-foot T.V. antenna stands on top of a building. From a point on the ground, the angle of elevation to the top and to the bottom of the antenna measures 56° and 42° respectively. How tall is the building?

Answers

Answer:

61.5

Step-by-step explanation:

In this case to calculate the height, we do the following:

The first is the graphic, attached image.

Then the calculations.

b / d = tan (42 °) = 0.9

d = b / 0.9

Then we have to:

(40 + b) / d = tan (56 °) = 1.48

(40 + b) = d * 1.48

Replacing we have:

(40 + b) = (b / 0.9) * 1.48

40 + b = 1.65 * b

1.65 * b - b = 40

b = 40 / 0.65

b = 61.5

Therefore the height is approximately 61.5

Final answer:

Using the tangent function of trigonometry for the two given angles, we can set up two equations. We solve these equations by substituting the fabricate distance from one into the other, providing the height of the building.

Explanation:

To find the height of the building, we'll use the tangent function of trigonometry. In this case, the tangent of an angle in a right triangle is defined as the opposite side divided by the adjacent side. Therefore, we create two equations using the two provided angles and the respective opposite sides (antenna and building + antenna), as we know the distances are proportional to the tangent of their angles when the adjacent side (distance from the point on the ground to the building) is the same.

For the entire structure (building + antenna): tan(56 degrees) = (Height of building + 40 feet) / Distance from the building.
For the antenna only: tan(42 degrees) = 40 feet / Distance from the building.

We can solve this system of equations by substitution. Since tan(42 degrees) = 40 feet / Distance from the building, it means the Distance from the building = 40 feet / tan(42 degrees). Plugging the Distance into equation 1 and solving for Height of building, we get: Height of building = tan(56 degrees) * Distance from building - 40 feet = tan(56 degrees) * (40 feet / tan(42 degrees)) - 40 feet. This gives us the height of the building.