Heat transfer is the flow of heat due to temperature difference.
The rate of increase in the energy content of the room is 1560 W.
Heat transfer is the flow of heat due to temperature difference. The heat flow from higher temperature to the lower temperature.
Given information-
Initial temperature of the room is 20 degree Celsius.
The room contains a 40-W light bulb, a 110-W TV set, a 300-W refrigerator, and a 1110-W iron.
The rate of increase in the energy of the room is the difference of energy increasing in the room and the energy leaving to the room.
Thus the rate of increase
Energy inside the room is the sum of all the energies increasing as,
As there is no heat transfer through the walls. Thus the energy leaving to the room is,
Thus put the values in the first equation as,
Thus the rate of increase in the energy content of the room is 1560 W.
Learn more about the heat transfer here;
The rate of increase of the energy content of the room when all electric devices are on is 1560 W.
To determine the rate of increase of the energy content of the room, we need to calculate the total power consumption of the electric devices. Adding up the power ratings, we have:
Total power = 40 W + 110 W + 300 W + 1110 W = 1560 W
Therefore, the rate of increase of the energy content of the room when all of these electric devices are on is 1560 W.
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b. False
Hitler and Mussolini headed two of the Axis powers of World War II.
a. True
b. False
1.
A. True.
He was very much influenced by the Bolshevik Revolution of Russian (1917) and founded his own Indochinese Communist Party in 1930. He led communist forces and fought against the French colonialism.
2.
A True,
The Hitler headed the Germany while as Mussolini headed Italy and both were allies of Axis powers.
B) 3.06 × 107 J
C) 2.46 × 1015 J
D) 6.30 × 1015 J
E) 8.82 × 1015 J
Answer:
1.1025×10^15Joules
No correct option
Explanation:
The type of energy possessed by the object is kinetic energy. Kinetic energy is the energy due to virtue of an object motion.
KE = 1/2MV² where;
M is the mass of the car = 0.05kg
V is the velocity of the car
Since the car is traveling at 0.7c (c is the speed of light)
speed = 0.7c { 0.7(3×10^8)}
Speed = 2.1×10^8
Substituting this values in the formula given we have;
KE = 1/2×0.05×(2.1×10^8)²
KE = 1.1025×10^15Joules
No correct option.
Answer:
the answer is =2.96 x10^-11 N
Explanation: