Given:
1.50 L of highly concentrated Pb(Clo3)2
0.300 L of 0.110 M NaI
Required:
mass precipitate of highly concentrated Pb(Clo3)2
Solution:
M1V1 = M2V2
M1(1.50 L of highly concentrated Pb(Clo3)2) = (0.300 L)(0.110 M NaI)
M1 = 0.022M Pb(Clo3)2 = 0.022 mol/L Pb(Clo3)2
Molar mass of Pb(Clo3)2= 374.2 g/mol
Mass of Pb(Clo3)2 = (0.022 mol/L Pb(Clo3)2)( 1.50 L)( 374.2 g/mol) = 12.35g Pb(Clo3)2
Answer : In an aqueous solution, a chloride ion is attracted to the hydrogen end of the water molecule.
Explanation :
The meaning of aqueous solution is the solution in which the solvent is water. In water molecule , oxygen atom is more electronegative than the hydrogen atom. That means, the hydrogen in the water molecule has partial positive charge and oxygen has partial negative charge.
As the chloride ion have the (-1) negative charge. So, it will be attracted towards the positive charge that is hydrogen end of the water molecule because opposite charges attract to each other.
Hence, in an aqueous solution, a chloride ion is attracted to the hydrogen end of the water molecule.
When 3.8 moles of zinc are mixed with copper (II) sulfate, the same number of moles of copper will be formed.
To determine the number of moles of copper formed when 3.8 moles of zinc are mixed with copper (II) sulfate, we need to consider the balanced chemical equation for the reaction.
Zn + CuSO4 → Cu + ZnSO4
The stoichiometry of the reaction tells us that 1 mole of zinc reacts with 1 mole of copper sulfate to produce 1 mole of copper. Therefore, if 3.8 moles of zinc are mixed with copper sulfate, the same number of moles of copper will be formed.
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It should be noted that controlling the rate of a chemical reaction is useful to the professions to improving production.
It should be noted that a chemicalreaction simply means the process by which substances are converted to another substance.
In this case, controlling the rate of a chemical reaction is useful to the professions to improving production.
By finding out how fast products are made, one can develop methods to into such production.
Learn more about chemical reaction on:
The years that will take or 52.5 g of a 60.0 g sample to decay to its daughter isotope is 807 years.
Half-life is the time required to decay or undergo half the process of any element.
Given the sample is 60.0 g in which 52.5 g sample has to be decay
so, 60 - 52.5 = 7.5 g
It can be seen that it goes three half life
60 >30 >15 >7.5
Now, the half life is 269
269 × 3 = 807 years.
Thus, the years taken are 807 years.
Learn more about isotopes
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