What mass precipitate will form of 1.50 L of highly concentrated Pb(Clo3)2 is mixed with 0.300 L of 0.110 M NaI

Answers

Answer 1
Answer:

Given:

1.50 L of highly concentrated Pb(Clo3)2

0.300 L of 0.110 M NaI

 

Required:

mass precipitate of highly concentrated Pb(Clo3)2

 

Solution:

M1V1 = M2V2

M1(1.50 L of highly concentrated Pb(Clo3)2) = (0.300 L)(0.110 M NaI)

M1 = 0.022M Pb(Clo3)2 = 0.022 mol/L Pb(Clo3)2

 

Molar mass of Pb(Clo3)2= 374.2 g/mol

Mass of Pb(Clo3)2 = (0.022 mol/L Pb(Clo3)2)( 1.50 L)( 374.2 g/mol) = 12.35g Pb(Clo3)2


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In an aqueous solution, a chloride ion is attracted to which end of the water molecule?

Answers

Answer : In an aqueous solution, a chloride ion is attracted to the hydrogen end of the water molecule.

Explanation :

The meaning of aqueous solution is the solution in which the solvent is water. In water molecule H_2O, oxygen atom is more electronegative than the hydrogen atom. That means, the hydrogen in the water molecule has partial positive charge and oxygen has partial negative charge.

As the chloride ion have the (-1) negative charge. So, it will be attracted towards the positive charge that is hydrogen end of the water molecule because opposite charges attract to each other.

Hence, in an aqueous solution, a chloride ion is attracted to the hydrogen end of the water molecule.

The end with the hydrogen atoms because the chloride ion is negatively charged while the hydrogen is positive. Hope this helps

How many moles of copper are formed when 3.8 moles of zinc are mixed with copper (II) sulfate?

Answers

CuSO₄+ Zn = Cu + ZnSO₄

1 mole Zn ---------> 1 mole Cu
3.8 mole Zn ------> ?

moles Cu = 3.8 x 1 / 1

= 3.8 moles of Cu

hope this helps!

Final answer:

When 3.8 moles of zinc are mixed with copper (II) sulfate, the same number of moles of copper will be formed.

Explanation:

To determine the number of moles of copper formed when 3.8 moles of zinc are mixed with copper (II) sulfate, we need to consider the balanced chemical equation for the reaction.

Zn + CuSO4 → Cu + ZnSO4

The stoichiometry of the reaction tells us that 1 mole of zinc reacts with 1 mole of copper sulfate to produce 1 mole of copper. Therefore, if 3.8 moles of zinc are mixed with copper sulfate, the same number of moles of copper will be formed.

Learn more about moles of copper here:

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As you go across a period the atomic radius decreases because...

Answers

More electrons pull together towards the nucleus.

Who developed a way of showing valence electrons?

Answers

American chemist Gilbert N. Lewis developeda way of showing valence electrons.
Gilbert N. Lewis was the scientist who developed a way of showing valence electrons.
:D

How is controlling the rate of a chemical reaction useful to a chemical engineer, physician and chef?

Answers

It should be noted that controlling the rate of a chemical reaction is useful to the professions to improving production.

What is a chemical reaction?

It should be noted that a chemicalreaction simply means the process by which substances are converted to another substance.

In this case, controlling the rate of a chemical reaction is useful to the professions to improving production.

By finding out how fast products are made, one can develop methods to into such production.

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Controlling the rate of chemical reactions is crucial to a chef because that is what gives food its flavor. Bread that rises too fast or slow (yeast cells converting glucose into carbon dioxide) will taste awful compared to correctly risen bread. Flambé undergoes a very fast, but brief, chemical reaction when the alcohol in which it is smothered is ignited, caramelizing the creme on top. A slow reaction would melt it all, while an even faster reaction could cause the dish to explode.

Argon-39 has a half-life of 269 years. How long will it take for 52.5 g of a 60.0 g sample to decay to its daughter isotope?

Answers

The years that will take or 52.5 g of a 60.0 g sample to decay to its daughter isotope is 807 years.

What is half-life?

Half-life is the time required to decay or undergo half the process of any element.

Given the sample is 60.0 g in which 52.5 g sample has to be decay

so, 60 - 52.5 = 7.5 g

It can be seen that it goes three half life

60 >30 >15 >7.5

Now, the half life is 269

269 × 3 = 807 years.

Thus, the years taken are 807 years.

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For 60.0 g sample, if it remains 60-52.5=7.5 g, it will go through 60->30->15->7.5, 3 half-life. So the time being taken is 269*3=807 years.