Answer:
hello :
the perimeter is : p = 2 ( w + l )
The area is : A= w ×l w : width l : length w ?
2 ( w + l ) = 76
w ×l = 336
you have the system :
w + l = 38 ...(1)
w ×l = 336...(2)
by (1) : l = 38 - w
subst in (2) : w ( 38 - w ) =336
38w - w²= 336
w² - 38w +336 = 0
delta = b² -4ac when : a = 1 and b= -38 c = 336
delta = (-38)² -4(1)(336) = 1444 - 1344 = 100 = 10²
w1 = (38-10)/2 = 14( the shorter sides length)
w2 = (38+10)/2 = 24( refused )
The shorter side's length of the rectangle is 24 inches. This is determined by solving the system of equations derived from the area (336 square inches) and perimeter (76 inches) constraints, resulting in a quadratic equation with two possible solutions, and the shorter side being 24 inches.
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Answer:
(-3,-3)
Step-by-step explanation:
I think that you meant to put 1/2x^2+3x+3/2. If so, the vertex is at point (-3,-3).
I graphed the equation down below.
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