What is the value of a?

5(a-4)-8a=55?
Please help :)

Answers

Answer 1

Answer: If you want to calculate 5*(a-4) - 8*a = 55, youhave to do few steps to get to know the value of the a.

5*a - 20 - 8*a = 55
-3*a = 55 + 20
-3*a = 75 /(-3)
a = - 25

The correct result and the value of the a is -25.

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a circle is divided into 18 equal parts how many degrees is the angle for each part? how many degrees is the angle for 5 parts? explain

Answers

There are 360 degrees in a circle, and we have 18 pieces, so we need to see how many times 18 goes into 360. We can find this out by dividing.

360/18=20

You can check this by multiplying 20 and 18 (it equals 360)!

So, each fraction of the circle will be 20 degrees.

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20*5=100. 5 parts will be 100 degrees.

Hope I helped! :)

1How can you arrange the digits 5,3,0 to create the greatest decimal possible? You can only use each digit once and you do not have to use all of the digits.

Answers

Answer:

0.530 (the 0 is not required)

Step-by-step explanation:

this is because another combination would be .35 which is less than .53 so this what i think the answer is.

--hope this helped :))

Four different sets of objects contain 4, 5, 6, and 8 objects, respectively. Howmany unique combinations can be formed by picking one object from each
set?

Answers

Answer:

960

Step-by-step explanation:

We can find the number of unique combinations by

Multiplying 4*5*6*8

960

There are 960 possible choices by picking 1 from each group

Yoshi and Rana serve muffins. There are three muffins with nuts. I/6 of the muffins have nuts. What fraction of the muffins do not have nuts?

Answers

So 6/6 subtract 1/6 is 5/6 and that's the answer

Think about it if you have 3 muffins answer 1/6 of them subtract 6 with 1 then put it over 6. So the answer would be 5/6.

Can any one help me any of them especially (b)

Answers

b.) $x^{- (1)/(2) }(x^{ (3)/(2) }-x^2)=x^{- (1)/(2) }(x^{ (3)/(2) })-x^{- (1)/(2) }(x^2)}=x^{- (1)/(2) + (3)/(2) }-x^{- (1)/(2) +2}=x-x^{ (1)/(2)$

e.) $(1)/( √(x) ) (x^2- √(x) )= \frac{1}{ x^{ (1)/(2) } } (x^2-x^ (1)/(2) ) \n = x^{- (1)/(2) } (x^2-x^ (1)/(2) )=x^{- (1)/(2) }(x^2)-x^{- (1)/(2) }(x^ (1)/(2) )} \n =x^{- (1)/(2) +2}-x^{- (1)/(2) + (1)/(2) }=x^ (1)/(2) -x^0=x^ (1)/(2) -1$