There are 25 students in Mrs. Venetozzi’s class at the beginning of the school year, and the average number of siblings for each student is 3. A new student with 8 siblings joins the class in November. What is the new class average for number of siblings? Round your answer to the nearest hundredth.

Answers

Answer 1

Answer: It is 25/3 which gives you 8.3 but let's say it is 8. So 8 students have 3 siblings and 9 have 2-0 siblings and 8 have 4-any number higher siblings. So if that kid joins there would be an avg of 3.63 siblings so 3.63 is the answer.

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A circle has an area of 75 square centimeters. Which answer is closest to the measure of its radius?

Answers

The formula of the area of a circle is
A = $\pi$ r²

75 cm² = $\pi$ r²
Divide by $\pi$ on either sides to isolate r

$(75)/( \pi )$ = $( \pi r^2)/( \pi )$
$\pi$ and $\pi$ cancels out

23.89 = r²
Take square roots to cancel power of two
$√(23.89)$ = $√(r^2)$
4.89 cm ≈ r
I dont know if the question had any options, but this is how we do it.

Answer:

4.9 for short

Step-by-step explanation:

Alex and his friends are studying for a geometry test and one of the main topics covered is parallel lines in a plane. They each write down what they think it means for two distinct lines in a plane to be parallel

Answers

Answer:

i rthink i understand your question but im not sure- I think you forgot to add a little bit of the question but im pretty sure your question is what is a parrllel line. IM going to answer that sorry if its wrong but im trying to be helpfull.

Step-by-step explanation:

Parallel lines are two lines that never intersect they start off beside each other and they stay where you can conect them with one line but they will never intercet.

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and

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Answer:

Literally, parallel lines are lines that extend in both directions without meeting.

The three definitions of parallel lines are correct, but Rachel's and Briana's definitions have flaws

Step-by-step explanation:

Rachel

The definition implies that two lines are said to be parallel if they are both perpendicular to another line.

This definition is correct, but the definition brings a new concept; it introduces the concept of line transversal.

Because the parallel lines can be defined without introducing the concept of line transversal (which was not part of the required definition), then we can conclude that the definition has a drawback.

Alex

Alex's definition is correct, and it has no drawback because the definition can be applied to concepts where parallel lines are used.

Briana

Here, Brianna introduced the concept of slopes.

Ideally, parallel lines have the same slope; but the concept is limited to slopes only; and cannot be applied to other concepts such as transversal of lines.

Please solve the math problem for me... I will mark you brainliest

Answers

Answer:

$x=34$

Step-by-step explanation:

*it's kind of hard to read the number in parenthesis though but i think it's 5

both angles have to add up to 180º because they are co-exterior angles on parallel lines.

$2(x+5)+102=180\n2(x+5)=78\n2x+10=78\n2x=68\nx=34$

If a number rounded to the nearest tenth is 10.1, which of the following could be the number?

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it could be 10.11 10.12 10.13 10.14
as long as the number next to the one is less than five it will become 10.1

What happens when Jonah is thrown into the sea?a. He drowns.
b. He is rescued by the people in a passing boat.
c. He finds that he can walk on water.
d. He is swallowed by a great fish.

Answers

Your answer would be D. He is swallowed by a great fish.

D Im 100% sure because im christian Because God told him to go preach and he refused to go and he went on a boat .GOd made a big storm and he feel or they pushed him and a bug fish got him

Trig help (Problems already solved)?The calculation for the problems are already done but I have to list a reason or what is being done in each step. "Each = and newline made" means a place I have to write what is being done in the calculation.

1. (secx + sinx)cotx = cscx + cosx
=(secx + sinx)cotx = cscx + cosx
=(1 / sinx) + cosx
=cscx + cosx

2. cosx + tanx sinx = secx
=cosx + tanx sinx = cosx + (sinx / cosx)sinx
=cosx + (sin^2x / cosx) = (1 / cosx)(cos^2x + sin^2x)
=1 / cosx
=secx

3. cscx - cosx cotx = sinx
=cscx - cosx cotx = (1 / sinx) - cosx(cosx / sinx)
=(1 / sinx) - (cos^2x / sinx)
=(1 - cos^2x) / sinx
=sin^2x / sinx = sinx

4. (cosx / (1 + cosx)) + (cosx / (1 - cosx)) = 2cotx cscx
=(cosx / (1 + cosx)) + (cosx / (1 - cosx)) = ((cosx (1 - cosx) + cosx (1 + cosx))) / (1 + cosx)(1 - cosx)
=(cosx - cos^2x + cosx + cos^2x) / (1 - cos^2x)
=2cosx / sin^2x
=2(cosx / sinx)(1 / sinx) = 2cotx cscx

Thank you to whoever decides to help me with explaining what is happening on each line.

Answers

The first identity uses the definition of the reciprocal functions $\sec x,\csc x,\cot x$ and the distributive property of multiplication.

$(\sec x+\sin x)\cot x=\left(\frac1{\cos x}+\sin x\right)(\cos x)/(\sin x)$
$=(\cos x)/(\cos x\sin x)+(\cos x\sin x)/(\sin x)$
$=\frac1{\sin x}+\cos x$
$=\csc x+\cos x$

The second uses the definition of $\tan x$ and the distributive property. Then a factor of $\frac1{\cos x}$ is pulled out, which allows you to use the identity $\sin^2x+\cos^2x=1$ .

$\cos x+\tan x\sin x=\cos x+(\sin x)/(\cos x)\sin x$
$=\cos x+(\sin^2x)/(\cos x)$
$=(\cos^2x)/(\cos x)+(\sin^2x)/(\cos x)$
$=\frac1{\cos x}\left(\cos^2x+\sin^2x\right)$
$=\frac1{\cos x}*1$
$=\frac1{\cos x}$
$=1$

The third uses the same ideas as the second: rewrite the reciprocal functions, then invoke the Pythagorean identity $\sin^2x+\cos^2x=1$ , which is equivalent to $\sin^2x=1-\cos^2x$ .

$\csc x-\cos x\cot x=\frac1{\sin x}-\cos x(\cos x)/(\sin x)$
$=\frac1{\sin x}-(\cos^2x)/(\sin x)$
$=\frac1{\sin x}\left(1-\cos^2x\right)$
$=\frac1{\sin x}\sin^2x$
$=(\sin^2x)/(\sin x)$
$=\sin x$

In the last one, you combine the fractions by enforcing common denominators. This lets you add the numerators together, and the denominator can be simplified. Once you do that, you rewrite the factors of cos and sin in the numerator and denominator to make up the cot and csc functions, and you're done.

$(\cos x)/(1+\cos x)+(\cos x)/(1-\cos x)=(\cos x(1-\cos x))/((1+\cos x)(1-\cos x))+(\cos x(1+\cos x))/((1-\cos x)(1+\cos x))$
$=(\cos x(1-\cos x)+\cos x(1+\cos x))/((1-\cos x)(1+\cos x))$
$=(\cos x(1-\cos x+1+\cos x))/(1-\cos^2x)$
$=(2\cos x)/(\sin^2x)$
$=2(\cos x)/(\sin x)\frac1{\sin x}$
$=2\cot x\csc x$

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