Correct answer=
gold is an element, it has a symbol of An
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Gold is an element, not a compound or a mixture. It is represented on the periodic table by the symbol Au and cannot be broken down into a simpler substance.
Gold is an element, not a compound or a mixture. It's one of the 118 known chemical elements, and it's represented on the periodic table by the symbol Au (from the Latin 'aurum'). As an element, gold consists of only one type of atom and cannot be broken down into a simpler substance. It differs from a compound, which is formed from two or more elements bonded together, and a mixture, where you can physically separate the individual components that make it up.
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Choose all answers that are correct.
A.
The addition of oxygen to the earth's atmosphere helped make possible the development of eukaryotic organisms, which need oxygen to carry out many of their life processes.
B.
When cyanobacteria evolved, they carried out photosynthesis. Oxygen is a product of photosynthesis. The addition of oxygen to earth’s atmosphere helped make possible the development of eukaryotic organisms, which need oxygen to carry out many of their life processes.
C.
The addition of oxygen to the earth's atmosphere helped make possible the development of prokaryotic organisms, which need oxygen to carry out many of their life processes.
D.
When cyanobacteria evolved, they carried out photosynthesis. Oxygen is needed to carry out photosynthesis.
Answer:
9.93
Explanation:
Your value for Kw is incorrect. The correct value is 5.48 × 10^-14.
pH + pOH = pKw
3.30 + pOH = -log(5.84 × 10^-14) = 13.23
pOH = 13.23 - 3.30 = 9.93
The pOH of the solution is 9.93.
The pOH of the solution is 10 .
Given that, the pH of the solution is 3.30, we also know that;
pH = - log[H^+]
Hence;
[H^+] = Antilog (-3.3)
[H^+] = 5.0 × 10^-4 M
But;
Kw = [H^+] [OH^-]
[OH^-] = Kw/[H^+]
The accurate value of Kw is 5.48 × 10^-14 not 5.48 x 10 9
[OH^-] = 5.48 x 10^-14/ 5.0 × 10^-4
[OH^-] = 1.1 x 10^-10 M
pOH = - log[1.1 x 10^-10 M]
pOH = 10
Learn more: brainly.com/question/1079292
Grams are the unit of the mass that is used to calculate the moles. From 37.5 gms of iron, 53.6 gms of ferric oxide are produced.
Mass is the measurement of the moles of the substance and the molar mass.
Moles of iron from the mass is calculated as:
Moles of iron = 37.5 gms ÷ 55.84 = 0.671 moles
The balanced chemical reaction:
4Fe + 3O2 → 2Fe2O3
From the above it is deduced that 4 moles of iron produce 2 moles of ferric oxide so, 0.671 moles of iron will produce,
(0.671 × 2) ÷ 4 = 0.3375 moles
Mass of ferric oxide, from moles, is calculated as:
Mass = 0.33 moles × 159.687
= 52.696 gms
Therefore, 53.6 gms of ferric oxide will be produced from 37.5 gms of iron.
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The mass of Fe2O3 that can be produced from 37.5g of iron (Fe) is approximately 53.65g. This is achieved by converting mass of iron to moles, using stoichiometry from the balanced chemical equation to convert moles of iron to moles of Fe2O3, and then converting moles of Fe2O3 back to grams.
First, we need to figure out the molar mass of iron (Fe) which is approximately 55.85 g/mol and the molar mass of iron(III) oxide (Fe2O3) which is approximately 159.69 g/mol. We find this using the atomic masses of Iron (Fe) and Oxygen (O) from the periodic table and add them appropriately.
Next, to find the number of moles of iron we use the provided mass of Fe and its molar mass. We calculate this as (37.5 g Fe / 55.85 g/mol Fe) = 0.671 moles of Fe. Now, the balanced chemical equation for the formation of iron(III) oxide is: 4Fe + 3O2 --> 2Fe2O3. From this balanced equation, we know that it takes 4 moles of iron (Fe) to produce 2 moles of Fe2O3. Therefore, the moles of Fe2O3 formed from 0.671 moles of Fe would be (0.671 moles Fe * 2 moles Fe2O3/4 moles Fe) = 0.336 moles of Fe2O3.
Finally, to find the mass of Fe2O3 produced, we multiply the moles of Fe2O3 by its molar mass. We calculate this as (0.336 moles Fe2O3 * 159.69 g/mol Fe2O3) = 53.657 g of Fe2O3.
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Answer:
A pill is usually absorbed into the blood through the stomach walls after it is swallowed – these can become active in a few minutes but usually take an hour or two to reach the highest concentration in the blood. IV drugs are injected directly into the blood work much faster – sometimes in seconds or minutes.