Answer : The correct option is, neutrons
Explanation :
Isotope : It is defined as the element that have the same number of protons but have the different number of neutrons of each of the atom.
Atomic number is defined as the number of protons or number of electrons.
Atomic number = number of protons = number of electrons
Mass number is defined as the sum of number of protons and number of neutrons.
Number of neutrons = Mass number - Number of protons
For example : Carbon - 13 isotope has mass number = 13, atomic number = 6 and the number of neutrons = 13 - 6 = 7
Hence, the isotopes of the same element have different numbers of neutrons.
Answer:
A. 3.36g of Na.
B. 14.62g of Ba3(PO4)2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
3Ba + 2Na3PO4 → 6Na + Ba3(PO4)2
Next, we shall determine the mass of Ba that reacted and the mass of Na and Ba3(PO4)2 produced from the equation.
This is illustrated below:
Molar Mass of Ba = 137g/mol
Mass of Ba from the balanced equation = 3 x 137 = 411g
Molar mass of Na = 23g/mol
Mass of Na from the balanced equation = 6 x 23 = 138g
Molar mass of Ba3(PO4)2 = (3 x 137) + 2[31 + (4x16)] = 411 + 2[31 + 64] = 601g/mol
Mass of Ba3(PO4)2 from the balanced equation = 1 x 601 = 601g
Summary:
From the balanced equation above,
411g of Ba reacted to produce 138g of Na and 601g of Ba3(PO4)2.
A. Determination of the mass of Na produced by reacting 10g of Ba.
From the balanced equation above,
411g of Ba reacted to produce 138g of Na.
Therefore, 10g of Ba will react to produce = (10 x 138)/411 = 3.36g of Na.
Therefore, 3.36g of Na is produced.
B. Determination of the mass of Ba3(PO4)2 produced by reacting 10g of Ba.
From the balanced equation above,
411g of Ba reacted to produce 601g of Ba3(PO4)2.
Therefore, 10g of Ba will react to produce = (10 x 601)/411 = 14.62g of Ba3(PO4)2.
Therefore, 14.62g of Ba3(PO4)2 is produced.
True or false?
Answer: The statement is false
Explanation:
Electrons occupy a region in atoms known as orbitals or subs hell. These orbitals include
I) S-orbital: it can occupy a maximum of two electrons
II) P-orbital: It occupies a maximum of six electrons
III) D-orbital: it occupies a maximum of ten electrons
F and G-orbitals as examples of other orbitals present.
A good illustration of the 6 electrons occupied by the P-subshell is seen in Sodium (Na) with atomic number of 11
Na = 1s2, 2S2 2p6, 3s1
Note: extra electrons are transferred to the next orbital