OX = 6.5
13=DX,
OX = 0.5*DX
13*0.5=6.5
A school has 800 students. 40% of the students are girls, the number of boys is 480.
To find the number of boys in the school, we can use the fact that 100% of the students minus the percentage of girls will give us the percentage of boys. In this case, if 40% of the students are girls, then 100% - 40% = 60% of the students are boys.
Now, we can calculate the number of boys:
Step 1: Calculate 60% of the total number of students (800).
60% of 800 = (60/100) * 800 = 0.6 * 800 = 480
So, 480 students are boys.
Therefore, in a school with 800 students, where 40% are girls, there are 480 boys.
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Answer:
A school has 800 students. 40% of the students are girls.
number girls : (800*40)/100=320
Find the number of boys
800-320=480
we ask for the number of boys not the %
or as you wrote 60% boys = (800*60)/100 =480
Step-by-step explanation:
Answer:
x = 5
Step-by-step explanation:
You can rewrite the right side, then equate the arguments of the log function.
4·ln(x) = 2·ln(25)
4·ln(x) = 2·ln(5^2)
4·ln(x) = 4·ln(5) . . . . . . . use the rule ln(a^b) = b·ln(a)
x = 5 . . . . . . . . . . . . . . . .divide by 4 and take the antilog
Answer:
x = 5
Step-by-step explanation:
Just as a note, you can look at x = 25 and know that it is not the answer. If it was, then you would get
4ln(25) = 2 ln(25) which reduces down to 4 = 2 when you divide by ln(25) on both sides.
4 ln(x) = 2 ln(25) Represent 25 as ln(5)^2
4 ln(x) = 2 ln(5)^2 The power on the right can be brought down.
4 ln(x) = 2 * 2 * ln(5) Divide both sides by 4
4 ln(x)/4 = 4 ln(5)/4
ln(x) = ln(5) Take the antiln of both sides.
antiln(ln(x)) = antiln(5)
x = 5
B) 3x+ 8 =1
C)1/2x+8=10
D)1/2(2x-6)=-6