Write an equation in standard form then solve 2q^2+22q+=-60

Answers

Answer 1

Answer: In standard form the equation reads 2q²+22q+60=0. In order to solve for q you have to factor the expression on the left first. Take out a factor of 2 and you have 2(q²+11q+30). Factor the inside and you have 2[(q+6)(q+5)]. Set the factors equal to 0 and solve and you finish with q=-6 or q=-5.

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Answers

Answer:

trump

Step-by-step explanation:

Can you solve (4x-3)/(x+2)+(15)/(x-3)

Answers

Please see the pic, I'd solved in it.

$(4x-3)/(x+2)$ + $(15)/(x-3)$ = 0
1st step: We need to have a common denominator.
So we do this:
$((4x-3)*(x-3))/((x+2)*(x-3))$ + $((15)*(x+2))/((x-3)*(x+2))$ = 0
2nd step: Distribute them
$(4x^(2)-3x-12x+9)/((x-3)(x+2))$ + $(15x+30)/((x+2)(x-3))$ = 0
3rd step: Do the rest of the equation!
We can put it on one fraction, its fine.
$(4x^2-15x+9+15x+30)/((x+2)(x-3))$ = 0
$(4x^2+39)/((x+2)(x-3))$ = 0 (-15 and 15 cancels out)
4th step: take the denominator to the other side
4x²+39 = 0 (anything × 0 = 0)
5th step: Take 39 to the other side
4x² = -39
6th step: Divide by 4 on both sides
$(4x^2)/(4)$ = $-(39)/(4)$
(4 and 4 cancels out)
x² = $-(39)/(4)$
7th step: Take the square root to keep x alone
x = $-\sqrt(39)/(4)$
It can also be written as:
x = $-( √(39) )/( √(4) )$
Final answer:
x = $-( √(39) )/(2)$

If Leah is 6 years older than her sister,Sue, and John is 5 years older than Leah, and the total of their ages is 41. Then how old is Sue?

Answers

Let us assume the age of Sue = x years
Then
Age of Leah = x + 6
Age of John = 5 + (x + 6)
= x + 11
Total of their ages = 41
So
x + x + 6 + x + 11 = 41
3x + 17 = 41
3x = 41 - 17
3x = 24
x = 24/3
= 8 years
So Sue is 8 years old.

She is 30 years old.

Negative X Plus 2y equals 6